anonymous
  • anonymous
A line passes through the point (–2, 4), and its y-intercept is (0, –6). What is the equation of the line that is perpendicular to the first line and passes through the point (5, –4)?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Phebe
  • Phebe
\(\color{RED}{WELCOME~TO~OPENSTUDY~}\)
anonymous
  • anonymous
Please just help me lol
Phebe
  • Phebe
LOL The equation of the line, in general form, that passes through the point (1, 1) and has a y-intercept of 2 is y=-x+2, or y=2-x

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Phebe
  • Phebe
@Owlcoffee
Owlcoffee
  • Owlcoffee
The y-intercept is but a notable point, but that point has to also belong to the line and the y-axis, which is an useful tool to find equation of lines. So, we will just find the slope of the given point and the y-interception of the first line and hopefully use the point-slope formula in order to find it's equation: \[m_1=\frac{ -6-4 }{ 0-(-2) }\]
anonymous
  • anonymous
|dw:1437160706203:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.