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anonymous

  • one year ago

A cylindrical vase has a diameter of 6 inches. At the bottom of the vase, there are 9 marbles, each of diameter 3 inches. The vase is filled with water up to a height of 12 inches. Which of the following could be used to calculate the volume of water in the vase? π(3in)2(12in) − 1.5(four over threeπ(9in)3) π(12in)2(3in) − 1.5(four over threeπ(9in)3) π(3in)2(12in) − 9(four over threeπ(1.5in)3) π(12in)2(3in) − 9(four over threeπ(1.5in)3)

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  1. anonymous
    • one year ago
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    idk this im so sorry

  2. Owlcoffee
    • one year ago
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    Now, first off, you have to calculate the volume of the cilider defined by the water and sustract it the volume of each individual marble. these are de equations you might want to use: \[A _{Cil.}= h \pi r^2 \] Where "h" is the height, and "r" the radius of the cilinder's base. \[A _{sph.}=\frac{ 4 }{ 3 } \pi r^3\] where "r" is the radius of the marble.

  3. Owlcoffee
    • one year ago
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    So, the volume of the water will be determined by the volume of the section it defines on the cilider sustracted by the volume of al lthe marbles: \[Vol=h. \pi . r^2 - 9(\frac{ 4 }{ 3 } \pi r ^3 )\]

  4. anonymous
    • one year ago
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    that eliminates a and c right?

  5. anonymous
    • one year ago
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    is it D? @Owlcoffee

  6. Owlcoffee
    • one year ago
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    yes.

  7. Owlcoffee
    • one year ago
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    I don't know, you'll have to replace the values and see.

  8. anonymous
    • one year ago
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    lol yeah thats what it matches

  9. Owlcoffee
    • one year ago
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    Yes, then "D" is the correct option.

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