## anonymous one year ago a culture started with 3,000 bacteria after 5 hours, it grew 3,900. bacteria. predict how many bacteria will be present after 9 hours. eound your answer to the nearet whole number. P=Ae^kt

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1. anonymous

Hm... I actually thought of this as a exponential funtions?

2. anonymous

its exponential growth

3. anonymous

hurry pleaseee i need help last question!!!

4. anonymous

OHHHHH i remember this. okay, so, any ideas

5. anonymous

Use P(0) find the value of A Then plug P(5) and find the value of K now u have your function P complete Just plug the P(9) and there you go

6. anonymous

so what ? srry confused i really need help like this is the last question

7. anonymous

I don't really know, this is just a guess, but 5,400 bacteria, maybe?

8. anonymous

$P(x)=Ae^{kt}$ this is the equation that models the population of bacteria We have as initial data that we started with 3000 bacteria, this means $P(0)=3000$ If we calculate $P(0)=A{e}^{k(0)}=A=3000$ we are able to find the value of A. Problem also says that after 5 hours, bacteria population is 3900 which is $P(5)=3900$ Evaluating t=5 on our main equation we would have $P(5)=3000{e}^{5k}=3900$ Solving this equation for k ${e}^{5k}=1.3$ $\ln {e}^{5k}=\ln 1.3$ $5k=\ln 1.3$ $k=\frac{ \ln 1.3 }{ 5 }$ We just found the value of k So our main equation should be $P(t)=3000{e}^{\frac{ \ln1.3 }{ 5 }t}$ So if we want to know what's the population of bacteria after 9 hours, we just evaluate t=9 in the equation $P(9)=3000{e}^{\frac{ \ln 1.3 }{ 5 } (9)}=4810.8$ which is roughly 4810 bacteria