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tmagloire1
 one year ago
If f(x) = 3a2x – 4 – ax, where a is some constant, find f ′(2).
tmagloire1
 one year ago
If f(x) = 3a2x – 4 – ax, where a is some constant, find f ′(2).

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jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0What class is this for?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0OK, that makes sense. I'm thinking... :)

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0answer choices: not enough information 1 0 DNE

princeharryyy
 one year ago
Best ResponseYou've already chosen the best response.0what do u think?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0EDIT: This one seems a bit strange... If you think about it, there are two possible values of 2x  4 either (2x  4) when x >= 2 or (2x  4) when x < 2. On one hand, f(x) = 3a(2x  4)  ax, so f'(x) = 6a  a = 5a, when x>= 2 On the other, f(x) = 3a(2x  4)  ax, so f'(x) = 6a  a = 7a, when x < 2. If a is not 0, then f'(2) is at a sharp point where the slopes 5a and 7a meet, which means it does not exist. However, if a = 0, then the slopes 5a and 7a are both 0, and f'(2) does exist. The best answer seems to be that there is not enough information. We need to know more about a.

princeharryyy
 one year ago
Best ResponseYou've already chosen the best response.0What, if I say the function doesn't exist if it has a =0.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Well, the zero function is a perfectly valid function. Set f(x) = 0. This is a true function that for every x returns the value 0.

princeharryyy
 one year ago
Best ResponseYou've already chosen the best response.0yes! that's what I was trying to tell you. You know the logic! great! what could this possibly mean. Do you still think there isn't enough information given to solve the problem.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure I'm seeing your point... But, please explain. :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Are you suggesting that a must equal 0, otherwise f'(2) can't be found?

princeharryyy
 one year ago
Best ResponseYou've already chosen the best response.0the exegesis is pretty simple, now that the value can be any integer and the function still stays a function, even when you put a as zero and also the second situation i.e. f'(2) still holds true when a is zero, that means a should be zero.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0OK, I see your point. I think this is a matter of interpretation of the question. The way I am reading it, a is "some constant" that is free to be whatever it wants before we ever even read the question. It is some given. That is why my answer is "not enough information." If we take your point of view, it would seem like a is "yet to be determined" and needs to be found to be something nice and convenient. Then, the answer would be f'(2) = 0. It depends on the author's original formulation. :)
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