anonymous
  • anonymous
The table below shows the number of marbles of different colors in a bag: Ursula draws a marble from the bag randomly without looking. She then draws another marble from the bag without replacing the first one. Which expression shows the probability of drawing black marbles in both the trials?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
A
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anonymous
  • anonymous
B AND C
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anonymous
  • anonymous
@welshfella @Vocaloid @vera_ewing @omgitsjc @LegendarySadist

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anonymous
  • anonymous
@Kash_TheSmartGuy
anonymous
  • anonymous
Where is the table?
anonymous
  • anonymous
here
anonymous
  • anonymous
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anonymous
  • anonymous
i was thinking the answer would be a but idk
anonymous
  • anonymous
Are you sure that's the table? The question asks about black marbles, but the table you provided only talks about Red, blue, green, and purple.
anonymous
  • anonymous
crap wrong table
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
there but i was thinking (a) but im not sure
anonymous
  • anonymous
When you look for a probability of one thing it's simply \[\large \sf \frac{Desired~object}{Total~objcets}\] Which in this case is \[\large \sf \frac{black~marbles}{Total~marbles}\] When you look for it to happen twice, you multiply the probabilities. Since we're assuming the first will end up with a loss of one black ( and one total ) the second probability would look like this \[\large \sf \frac{black~marbles-1}{Total~marbles-1}\] Now you would just multiply the probabilities together so \[\large \sf \frac{black~marbles}{Total~marbles}~\times ~ \large \sf \frac{black~marbles-1}{Total~marbles-1}\]
anonymous
  • anonymous
would it be a thats what i got
anonymous
  • anonymous
No, it's not a
anonymous
  • anonymous
c
anonymous
  • anonymous
or b idk
anonymous
  • anonymous
Why not just plug the numbers into what I gave you?
anonymous
  • anonymous
\[\large \sf \frac{black~marbles}{Total~marbles}~\times ~ \large \sf \frac{black~marbles-1}{Total~marbles-1}\]
anonymous
  • anonymous
idkhowwwwwwwwwwwwwwwwwwwwwwwwwwwwww
anonymous
  • anonymous
How many black marbles are there?
anonymous
  • anonymous
10
anonymous
  • anonymous
How many total marbles are there?
anonymous
  • anonymous
16
anonymous
  • anonymous
@LegendarySadist
anonymous
  • anonymous
Now plug 10 in for black marbles and 16 for total marbles \[\large \sf \frac{black~marbles}{Total~marbles}~\times ~ \large \sf \frac{black~marbles-1}{Total~marbles-1}\]
anonymous
  • anonymous
d
anonymous
  • anonymous
You only showed A B and C as your options.
anonymous
  • anonymous
soooooooo what is it @LegendarySadist

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