## anonymous one year ago If the hypotenuse of a 45°-45°-90° triangle is 13, what is the length of one of the legs?

1. anonymous

In a 45-45-90 triangle, the leg can always be found by $\large \sf Leg~=~\frac{1}{2} H \sqrt{2}$

2. anonymous

A) 13 square root 5 / 5 B) 13 square root 2 / 2 C) 13 square root 3 D) 13 square root 5

3. wolf1728

13/sqrt(2) http://www.1728.org/trig2.htm

4. anonymous

over 2?

5. wolf1728

I calculate 13/sqrt(2)

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