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yisrael012332

  • one year ago

A system of equations is shown below: -3x + 7y = -16 -9x + 5y = 16 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points) Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points)

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  1. yisrael012332
    • one year ago
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    @SithsAndGiggles

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    • one year ago
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    @wolf1728

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    • one year ago
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    • one year ago
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  9. yisrael012332
    • one year ago
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    help please....

  10. princeharryyy
    • one year ago
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    I can't do the steps as if now, that will take time and I've got a lot of work to do. Sorry about that.

  11. yisrael012332
    • one year ago
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    ok

  12. yisrael012332
    • one year ago
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    anyone else im so lost

  13. Owlcoffee
    • one year ago
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    To create a new system of equation with the conditions given, let's take for example the first equation: \[-3x+7y=-16\] And let's forget about the "=" sign and center on the following expression: \[-3x+7y+16\] So I will add to it the second equation, multiplied by any number... let's say... 10... \[(-3x+7y+16)+(10)(-9x+5y-16)\] So, doing some simple algebra: \[(-3x+7y+16)-90x+50y-160\] Ending up with: \[-93x+57y-144\] And for the second part you'll have to solve the new system of equation formed by the new equation: \[-93x+57y=144\] \[-9x+5y=16\]

  14. yisrael012332
    • one year ago
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    ty so much

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