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Needhelpp101
 one year ago
At a temperature of 320K, the gas in a cylinder has a volume of 40.0 liters. If the volume of the gas is decreased to 20.0 liters, what must the temperature be for the gas pressure to remain constant?
A. 160 K
B. 273 K
C. 560 K
D. 140 K
Needhelpp101
 one year ago
At a temperature of 320K, the gas in a cylinder has a volume of 40.0 liters. If the volume of the gas is decreased to 20.0 liters, what must the temperature be for the gas pressure to remain constant? A. 160 K B. 273 K C. 560 K D. 140 K

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perl
 one year ago
Best ResponseYou've already chosen the best response.1according to this https://www.chem.wisc.edu/deptfiles/genchem/sstutorial/Text9/Tx95/tx95.html

perl
 one year ago
Best ResponseYou've already chosen the best response.1Charles' Law states: If the pressure of a gas sample is kept constant, the volume of the sample will vary directly with the temperature in Kelvin (Figure 9.9).

perl
 one year ago
Best ResponseYou've already chosen the best response.1this means T = k * V 320 = k * 40 k = 320/40 = 8 T = 8*V Can you solve it now?

danica518
 one year ago
Best ResponseYou've already chosen the best response.1P1*V1=n*R*320K P2*V2=n*R*T2 P2=P1 and V2=20.0 or 1/2 of V1 so P2*V2= P1*1/2V1=1/2(P1*V1)=1/2( n*R*320K)= n*R*160K therefore 160K
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