anonymous
  • anonymous
What is the simplified form of 24 y to the eighth power over 15 x to the fifth power divided by 8 y to the fourth power over 4 x squared?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
|dw:1437172442205:dw|
anonymous
  • anonymous

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anonymous
  • anonymous
When you divide fractions, you flip the 2nd one, so do that and you get: |dw:1437172594149:dw|
anonymous
  • anonymous
Then you can simplify the numbers|dw:1437172703177:dw|
anonymous
  • anonymous
And finally you use exponent rules when dividing and end up with|dw:1437172811181:dw|
anonymous
  • anonymous
That's not an answer choice :(
anonymous
  • anonymous
a. 4y^3/5x^4 b. 4y^4/5x^3 c. 5x^4/4y^3 d. 5x^3/4y^4
amistre64
  • amistre64
you wrote x^2 instead of x^5
anonymous
  • anonymous
Me?
anonymous
  • anonymous
Yeah :P
amistre64
  • amistre64
yeah |dw:1437173058441:dw|
anonymous
  • anonymous
So it'll be b. 4y^4/5x^3 i'm pretty sure
anonymous
  • anonymous
Oh! my bad! It was suppose to be 15x^5
amistre64
  • amistre64
|dw:1437173083316:dw|
amistre64
  • amistre64
|dw:1437173131450:dw|
amistre64
  • amistre64
its at least y^4/x^3 yes
anonymous
  • anonymous
So yeah, when you simplify it would be B :)
anonymous
  • anonymous
Can I ask one more? I have the answer, I just need someone to check it.
amistre64
  • amistre64
maybe
anonymous
  • anonymous
What is the simplified form of the quantity 4 z squared plus 16z plus 15 over the quantity 2 z squared minus z minus 15?
anonymous
  • anonymous
|dw:1437173334382:dw|
amistre64
  • amistre64
whats your thought?
anonymous
  • anonymous
I got 2x+3/x+3
anonymous
  • anonymous
factor I suppose
amistre64
  • amistre64
factor is ideal yes
anonymous
  • anonymous
4x^2+10x+6x+15= (2x+3)(2x+5)
anonymous
  • anonymous
Over (2x+5)(x-3)
amistre64
  • amistre64
|dw:1437173377211:dw|
amistre64
  • amistre64
thats what i get as well
anonymous
  • anonymous
So would the answer be 2x+3/x-3 ?
amistre64
  • amistre64
yes
anonymous
  • anonymous
tHANKS:)
amistre64
  • amistre64
good luck :)

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