- anonymous

What is the discontuinty of f(x) = the quantity negative x squared plus x plus 20 over the quantity x plus 4?

- jamiebookeater

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- anonymous

- anonymous

|dw:1437190829325:dw|

- anonymous

So I think it is -4?

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## More answers

- anonymous

Am I right?

- Astrophysics

So you're taking \[\lim_{x \rightarrow -4} f(x)\]

- anonymous

Um..I suppose:).

- Astrophysics

Mhm, you know calculus?

- anonymous

No. It's Algebra 2

- Astrophysics

But yes, that's right -4

- Astrophysics

As the domain is all real numbers where x cannot equal -4.

- Astrophysics

So you're looking for what x is basically then, so factor the top, that should give it away :)

- Astrophysics

To find the zeros you have to factor the numerator, it's just finding the roots, hence x.

- anonymous

So (x-4)(x+5)

- anonymous

do I just plug in -4?

- Astrophysics

You should've got -(x+4)(x-5)

- anonymous

So it is (-4,1)

- Astrophysics

Then you can cancel out the numerator and denominator of (x+4) and you'll have x = 5 as your zero

- anonymous

So, if I were to graph it, the point would be -4,1 ? Correct?

- anonymous

Is it working now?

- Astrophysics

Oh I see what you mean now, so if we take the limit we would indeed get = 9

- Astrophysics

I really can't remember doing it in algebra 2, mhm I will have to do some research

- anonymous

haha<3 Ok! Thank-you:)

- anonymous

What is the graph of the function f(x) = the quantity of negative x squared minus 2 x minus 2, all over x minus 2?

- Astrophysics

use this site to graph https://www.desmos.com/calculator

- anonymous

I don't mean to post another question because usually I can figure things out by myself, but I can't graph usind desmos. It won't work

- anonymous

Maybe I'm doing it wrong. Because when I typed it in, I only got one graph when it should have been two. Like 2 lines:)

- anonymous

Any thoughts?

- Astrophysics

Well, you can't put words if that's what you're trying, so what do those words tell us mathematically?

- anonymous

-x^2-2x-2/x-2

- anonymous

And I didn't :) I typed in that

- Astrophysics

I got this, make sure you put y = , or f(x) = |dw:1437192565745:dw|

- anonymous

Ok:) But shouldn't there two?

- anonymous

Nevermind! Thank-you<3

- Astrophysics

Np ^.^

- anonymous

\[A\ function\ f(x)\ is\ said\ tobe\ continuous\ at\ a\ point\ x=c \ of\ its\ domain\\ \iff\ \lim_{x \rightarrow c}=f(c).\]

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