anonymous
  • anonymous
Find the value of x.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Find the value of X. http://scde.mrooms.org/file.php/2247/Images/Ch10Test/10_6.JPG
anonymous
  • anonymous
can someone please help me?
anonymous
  • anonymous
can someone please help me?

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anonymous
  • anonymous
the link asks for a log in
jdoe0001
  • jdoe0001
url requires a login so... ahemm, take a quick screenshot of the material, crop it and post it here
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
can you see it now?
anonymous
  • anonymous
yes, is it multiple choice ?
anonymous
  • anonymous
no it just says to find the value of x
anonymous
  • anonymous
if the arc lengths of a circle are equal, then these chords of the same circle are also equal
anonymous
  • anonymous
chords making those arc lengths.
jdoe0001
  • jdoe0001
yeap... notice the "tickmarks" |dw:1437177463813:dw|
anonymous
  • anonymous
so set them equal to each other. right ?
anonymous
  • anonymous
yes
jdoe0001
  • jdoe0001
no, those lines don't mean the circle is growing hair are tickmarks pointing out the EQUALity of the arcs
anonymous
  • anonymous
so would x=28?
jdoe0001
  • jdoe0001
well... |dw:1437177639960:dw|
jdoe0001
  • jdoe0001
hmm shoot.. should be a minus there |dw:1437177712846:dw|
anonymous
  • anonymous
@gatey so do you only want the answer or do you actually want to understand the problem?
anonymous
  • anonymous
can i have both please and thank you
anonymous
  • anonymous
12x-8=5x+13 that is the first step you need to do set them equal to eachother. then you need to subtract 5x from 12x getting the equation 7x-8=13 then you add the 8 to the 13 and get the equation 7x=21 divide by 7x making x=3
anonymous
  • anonymous
got it ?
anonymous
  • anonymous
YES!! i made a mistake by plugging 3 into the 12x-8 equation when i shouldn't have. thank you
anonymous
  • anonymous
but i have another problem i need your help on, i was hoping you could help me?
anonymous
  • anonymous
maybe i can
anonymous
  • anonymous
but post it as a new question

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