anonymous
  • anonymous
Find the average rate of change from x = 10 to x = 17 for the function f(x) = 0.01(2)^x and select the correct answer below. A)10.24 B)185.78 C)1300.48 D)1310.72
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@jim_thompson5910 ???
jim_thompson5910
  • jim_thompson5910
if x = 10, then f(x) = ???
anonymous
  • anonymous
17?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
replace x with 10 and evaluate the function
jim_thompson5910
  • jim_thompson5910
f(x) = 0.01(2)^x f(10) = 0.01(2)^10 f(10) = ???
anonymous
  • anonymous
10.24?
anonymous
  • anonymous
Just a guess, but A 10.24
jim_thompson5910
  • jim_thompson5910
10.24 isn't the answer, but it helps get us there
anonymous
  • anonymous
I am not really sure though
anonymous
  • anonymous
:(
jim_thompson5910
  • jim_thompson5910
if x = 17, then f(x) = ???
anonymous
  • anonymous
This might help: https://mathway.com/examples/Algebra/Functions/Finding-the-Average-Rate-of-Change?id=769
anonymous
  • anonymous
0.01(2)
anonymous
  • anonymous
? @jim_thompson5910 ?
jim_thompson5910
  • jim_thompson5910
f(x) = 0.01(2)^x f(17) = 0.01(2)^17 f(17) = ???
anonymous
  • anonymous
sorry, I don't know
anonymous
  • anonymous
13?
jim_thompson5910
  • jim_thompson5910
what is 0.01(2)^17 equal to
anonymous
  • anonymous
WAIT its the answer D?
jim_thompson5910
  • jim_thompson5910
nope, it helps us get there though
jim_thompson5910
  • jim_thompson5910
f(10) = 10.24 f(17) = 1310.72
jim_thompson5910
  • jim_thompson5910
now evaluate \[\Large \frac{f(17)-f(10)}{17-10}\]
anonymous
  • anonymous
-17 f(10) +f(17) -10?
anonymous
  • anonymous
its right?
jim_thompson5910
  • jim_thompson5910
\[\Large \frac{f(17)-f(10)}{17-10} = \frac{1310.72-10.24}{17-10} = ???\]
anonymous
  • anonymous
1300
anonymous
  • anonymous
?
anonymous
  • anonymous
1300.1*
jim_thompson5910
  • jim_thompson5910
what is 1310.72-10.24 equal to? what is 17-10 equal to? divide those two results
anonymous
  • anonymous
what is 1310.72-10.24 equal to 1300.48 what is 17-10 equal to 7
anonymous
  • anonymous
im right?
anonymous
  • anonymous
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
now divide 1300.48/7
anonymous
  • anonymous
185.7?
jim_thompson5910
  • jim_thompson5910
185.78
anonymous
  • anonymous
185.78
anonymous
  • anonymous
yea sorry
jim_thompson5910
  • jim_thompson5910
yeah
jim_thompson5910
  • jim_thompson5910
its ok
anonymous
  • anonymous
soits b?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
thank you, can you check something if make sure if im right?
anonymous
  • anonymous
Identify the type of sequence shown in the table below and select the appropriate response. n f(n) 1 12 2 −36 3 108 4 −324 5 972
anonymous
  • anonymous
A)Arithmetic sequence; common difference is −48 B)Arithmetic sequence; common difference is 144 C)Geometric sequence; common ratio is −3 D)Geometric sequence; common ratio is 3
anonymous
  • anonymous
I THINK ITS C, but im not sure
anonymous
  • anonymous
im right?
jim_thompson5910
  • jim_thompson5910
why C?
anonymous
  • anonymous
i dont know somebody give the answer
anonymous
  • anonymous
@jim_thompson5910 ???
anonymous
  • anonymous
are u there? @jim_thompson5910 ??/
jim_thompson5910
  • jim_thompson5910
have a look at this article https://purplemath.com/modules/series3.htm

Looking for something else?

Not the answer you are looking for? Search for more explanations.