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anonymous

  • one year ago

Challenge: Graph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the circle. Write the equation of the circle.

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  1. jdoe0001
    • one year ago
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    hmm what's the distance between (-3, 4) and (5, -2). ? |dw:1437177936311:dw|

  2. anonymous
    • one year ago
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    eq.of circle is (x-x1)(x-x2)+(y-y1)(y-y2)=0

  3. anonymous
    • one year ago
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    About 9.90

  4. anonymous
    • one year ago
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    So I divide that by two to get the radius right? And with it the center

  5. jdoe0001
    • one year ago
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    @sewandowski hmmm how did you get 9.9?

  6. anonymous
    • one year ago
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    Square root of: (-3-4)^2 + (5-(-2))^2

  7. anonymous
    • one year ago
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    mid point is the center

  8. anonymous
    • one year ago
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    Oooh, so I use the midpoint formula?

  9. anonymous
    • one year ago
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    yes

  10. jdoe0001
    • one year ago
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    hmm anyhow as @surjithayer said find the diameter to get the "radius" ahd the midpoint formula to get the center

  11. jdoe0001
    • one year ago
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    btw, the distance aint' 9.9 either

  12. anonymous
    • one year ago
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    Ok, so the midpoint of the points is (1,1), which is the center

  13. jdoe0001
    • one year ago
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    yeap...1,1 is the center

  14. jdoe0001
    • one year ago
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    and the diameter?

  15. anonymous
    • one year ago
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    Ok, now I got 10

  16. anonymous
    • one year ago
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    so the radius is 5

  17. jdoe0001
    • one year ago
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    yeap radius is 5, diameter is 10 then \(\large (x-{\color{brown}{ h}})^2+(y-{\color{blue}{ k}})^2={\color{purple}{ r}}^2 \qquad center\ ({\color{brown}{ h}},{\color{blue}{ k}})\qquad radius={\color{purple}{ r}}\)

  18. anonymous
    • one year ago
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    Perfect, now all I need to do is graph

  19. anonymous
    • one year ago
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    Thanks guys!!

  20. jdoe0001
    • one year ago
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    yw

  21. anonymous
    • one year ago
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    eq. of circle is \[\left\{ x-\left( -3 \right) \right\}\left( x-5 \right)+\left( y-4 \right)\left\{ y-\left( -2 \right) \right\}=0\] solve it.

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