## anonymous one year ago Challenge: Graph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the circle. Write the equation of the circle.

1. jdoe0001

hmm what's the distance between (-3, 4) and (5, -2). ? |dw:1437177936311:dw|

2. anonymous

eq.of circle is (x-x1)(x-x2)+(y-y1)(y-y2)=0

3. anonymous

4. anonymous

So I divide that by two to get the radius right? And with it the center

5. jdoe0001

@sewandowski hmmm how did you get 9.9?

6. anonymous

Square root of: (-3-4)^2 + (5-(-2))^2

7. anonymous

mid point is the center

8. anonymous

Oooh, so I use the midpoint formula?

9. anonymous

yes

10. jdoe0001

hmm anyhow as @surjithayer said find the diameter to get the "radius" ahd the midpoint formula to get the center

11. jdoe0001

btw, the distance aint' 9.9 either

12. anonymous

Ok, so the midpoint of the points is (1,1), which is the center

13. jdoe0001

yeap...1,1 is the center

14. jdoe0001

and the diameter?

15. anonymous

Ok, now I got 10

16. anonymous

17. jdoe0001

yeap radius is 5, diameter is 10 then $$\large (x-{\color{brown}{ h}})^2+(y-{\color{blue}{ k}})^2={\color{purple}{ r}}^2 \qquad center\ ({\color{brown}{ h}},{\color{blue}{ k}})\qquad radius={\color{purple}{ r}}$$

18. anonymous

Perfect, now all I need to do is graph

19. anonymous

Thanks guys!!

20. jdoe0001

yw

21. anonymous

eq. of circle is $\left\{ x-\left( -3 \right) \right\}\left( x-5 \right)+\left( y-4 \right)\left\{ y-\left( -2 \right) \right\}=0$ solve it.