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anonymous
 one year ago
Challenge: Graph the equation with a diameter
that has endpoints at (3, 4) and (5, 2). Label
the center and at least four points on the
circle. Write the equation of the circle.
anonymous
 one year ago
Challenge: Graph the equation with a diameter that has endpoints at (3, 4) and (5, 2). Label the center and at least four points on the circle. Write the equation of the circle.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm what's the distance between (3, 4) and (5, 2). ? dw:1437177936311:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0eq.of circle is (xx1)(xx2)+(yy1)(yy2)=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I divide that by two to get the radius right? And with it the center

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@sewandowski hmmm how did you get 9.9?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Square root of: (34)^2 + (5(2))^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0mid point is the center

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oooh, so I use the midpoint formula?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm anyhow as @surjithayer said find the diameter to get the "radius" ahd the midpoint formula to get the center

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0btw, the distance aint' 9.9 either

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, so the midpoint of the points is (1,1), which is the center

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeap...1,1 is the center

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeap radius is 5, diameter is 10 then \(\large (x{\color{brown}{ h}})^2+(y{\color{blue}{ k}})^2={\color{purple}{ r}}^2 \qquad center\ ({\color{brown}{ h}},{\color{blue}{ k}})\qquad radius={\color{purple}{ r}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Perfect, now all I need to do is graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0eq. of circle is \[\left\{ x\left( 3 \right) \right\}\left( x5 \right)+\left( y4 \right)\left\{ y\left( 2 \right) \right\}=0\] solve it.
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