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anonymous
 one year ago
Graph the equation with a diameter that has endpoints at (2, 2) and (4, 2).
Label the center and at least four points on the
circle. Write the equation of the circle.
anonymous
 one year ago
Graph the equation with a diameter that has endpoints at (2, 2) and (4, 2). Label the center and at least four points on the circle. Write the equation of the circle.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Heey, this is kinda the same question as befre, but I don't think my answer for distance is correct

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hmm what did you get for the distance?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hmm is there a radical form for it?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0well. you used the distance formula to get it.... so... that means you'd have a root of it something like \(\bf distance = \sqrt{\qquad}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[Distance= \sqrt{(24)^2+(22)^2}\]

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0yeap... I got the same, which in decimal form is about 7.21 so, that's correct \(\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 2}}\quad ,&{\color{blue}{ 2}})\quad % (c,d) &({\color{red}{ 4}}\quad ,&{\color{blue}{ 2}}) \end{array}\qquad % distance value d = \sqrt{6^2+4^2}\implies d=\sqrt{52}\impliedby diameter \\ \quad \\ radius=\cfrac{\sqrt{52}}{2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the radius would be 3.60

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0using the midpoint formula, the center is at 1,0 thus \(\large (x{\color{brown}{ h}})^2+(y{\color{blue}{ k}})^2={\color{purple}{ r}}^2 \qquad center\ ({\color{brown}{ 1}},{\color{blue}{ 0}})\qquad radius={\color{purple}{ \frac{\sqrt{52}}{2}}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wouldn't the center be (1,1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oops, nevermind, my bad, it is 0

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0shoot.. a bit truncated...lemme redo that

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf (x{\color{brown}{ h}})^2+(y{\color{blue}{ k}})^2={\color{purple}{ r}}^2 \qquad center\ ({\color{brown}{ 1}},{\color{blue}{ 0}})\qquad radius={\color{purple}{ \frac{\sqrt{52}}{2}}} \\ \quad \\ \quad \\ (x{\color{brown}{ 1}})^2+(y{\color{blue}{ 0}})^2=\left( {\color{purple}{ \frac{\sqrt{52}}{2}}}\right)^2 \\ \quad \\ (x1)^2+y=\cfrac{(\sqrt{52})^2}{2^2}\implies (x1)^2+y=\cfrac{\cancel{52}}{\cancel{4}} \\ \quad \\ \implies (x1)^2+y=13\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the square root is cancelled off in the equation but I still have a radius of 3.60 right?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0if you want the decimal form of it, yes the advantage of the radical form is that, it doesn't have any missing floating values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, but I need the decimal so that I can graph it

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0but yes, 7.21 is a rounded up version, you lose a few decimals there half that is 3.6, also rounded up, again losing a few decimals

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0welll. yes sure.. but yes, is 3.6 :)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437188896778:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0radius is 1/2 the diameter endpoints (2,2) and ( 4,2) diameter = 6 units so radius = 3 units for the x value 2 +3 or 4 3 = 1 from end to the center = 3 units 2 3 = 1 so the y value for the center = 1

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0oops I did 2, 2 should be 2, 2 sorry

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437190476623:dw
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