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briana.img

  • one year ago

Find the number of ways to listen to 4 different CDs from a selection of 15 CDs.

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  1. briana.img
    • one year ago
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    I thought it was 15*14*13*12 but it's not

  2. jim_thompson5910
    • one year ago
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    That would be the answer if order mattered, but it does not matter

  3. jim_thompson5910
    • one year ago
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    Let's say you had 4 CDs labeled A,B,C,D there are 4! = 4*3*2*1 = 24 ways to arrange the four letters (eg: ABCD or ACBD) you have to divide the answer you got by 24 to account for the fact that order doesn't matter

  4. briana.img
    • one year ago
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    aaaah okay okay so 1365

  5. jim_thompson5910
    • one year ago
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    Smaller example Let's say you had 4 CDs (A,B,C,D) and you pick 2 of them. order doesn't matter 4*3 = 12 if order mattered. The full list of choices is AB, BA AC, CA AD, DA BC, CB BD, DB CD, DC notice how the list above is double of what it should be. We've counted everything twice. Which is why we divide by 2! = 2*1 = 2 to get 12/2 = 6. There are 6 ways to pick the two CDs where order doesn't matter

  6. jim_thompson5910
    • one year ago
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    yes it is 1365 an alternative route is to use the combination formula \[\Large C(n,r) = \frac{n!}{r!*(n-r)!}\]

  7. briana.img
    • one year ago
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    aaaaah okay okay!!

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