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anonymous

  • one year ago

HELP PLZ WILL MEDAL AND FAN A firecracker has dimensions as shown. Height is 14 cm, radius is 1 cm and slant height of the cone is 2 cm. Paper covers the entire surface area including the cone, the lateral area and the bottom circle but does not include the tail. What is the best approximate area of paper needed to wrap the firecracker? (Use three point one four for pi. Round your answer to the nearest whole number.)

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  1. Mertsj
    • one year ago
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    Find the surface area of the cylindrical part first: Surface Area = 2 pi r h

  2. triciaal
    • one year ago
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    my approach would be to find the base area of the cylinder add the surface area of the cylinder add the surface area of the cone

  3. Mertsj
    • one year ago
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    |dw:1437186893264:dw|

  4. anonymous
    • one year ago
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    SO I DO 2X14X3.14

  5. Mertsj
    • one year ago
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    yes

  6. anonymous
    • one year ago
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    okay that got 87.92

  7. Mertsj
    • one year ago
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    Then find the area of the conical part. The formula is Surface Area = pi r L where L is the slant height.

  8. Mertsj
    • one year ago
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    Then add the two answers together.

  9. anonymous
    • one year ago
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    can you draw a picture please

  10. Mertsj
    • one year ago
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    |dw:1437187206716:dw|

  11. anonymous
    • one year ago
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    6.28

  12. anonymous
    • one year ago
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    94.2 is my answer

  13. triciaal
    • one year ago
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    |dw:1437192121647:dw|

  14. triciaal
    • one year ago
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    I think you forgot the bottom circle

  15. triciaal
    • one year ago
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    remember to round to the nearest whole number.

  16. Mertsj
    • one year ago
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    Yes. Add the bottom circle.

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