anonymous
  • anonymous
HELP PLZ WILL MEDAL AND FAN A firecracker has dimensions as shown. Height is 14 cm, radius is 1 cm and slant height of the cone is 2 cm. Paper covers the entire surface area including the cone, the lateral area and the bottom circle but does not include the tail. What is the best approximate area of paper needed to wrap the firecracker? (Use three point one four for pi. Round your answer to the nearest whole number.)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
https://racine.brainhoney.com/Resource/26948139,0/Assets/flvs/math1_v10_gs-xml/res0115/08_11c_13_019.jpg
Mertsj
  • Mertsj
Find the surface area of the cylindrical part first: Surface Area = 2 pi r h
triciaal
  • triciaal
my approach would be to find the base area of the cylinder add the surface area of the cylinder add the surface area of the cone

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Mertsj
  • Mertsj
|dw:1437186893264:dw|
anonymous
  • anonymous
SO I DO 2X14X3.14
Mertsj
  • Mertsj
yes
anonymous
  • anonymous
okay that got 87.92
Mertsj
  • Mertsj
Then find the area of the conical part. The formula is Surface Area = pi r L where L is the slant height.
Mertsj
  • Mertsj
Then add the two answers together.
anonymous
  • anonymous
can you draw a picture please
Mertsj
  • Mertsj
|dw:1437187206716:dw|
anonymous
  • anonymous
6.28
anonymous
  • anonymous
94.2 is my answer
triciaal
  • triciaal
|dw:1437192121647:dw|
triciaal
  • triciaal
I think you forgot the bottom circle
triciaal
  • triciaal
remember to round to the nearest whole number.
Mertsj
  • Mertsj
Yes. Add the bottom circle.

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