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kcruz99
 one year ago
A geometric sequence is defined by the explicit formula a_n=5(4)^n1. what is the recursive formula for the nth term of this sequence?
A an=4a_n1
Ba_n+1=4a_n
C a_n+1=5a_n
D a_n=5a_n1
whenever there is an underscore(_) it means that the letter should be down, if that makes sense lol.
Will medal and fan!
kcruz99
 one year ago
A geometric sequence is defined by the explicit formula a_n=5(4)^n1. what is the recursive formula for the nth term of this sequence? A an=4a_n1 Ba_n+1=4a_n C a_n+1=5a_n D a_n=5a_n1 whenever there is an underscore(_) it means that the letter should be down, if that makes sense lol. Will medal and fan!

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freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[a_n=5(4)^{n1} \\ a_{n+1}=5(4)^{n} \\ \text{ also notice } a_n=5(4)^n(4)^{1} \\ \text{ do you notice what you can replace } 5(4)^n \text{ with ?}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1and I notice that one number is 4 so replace my 4's with 4's

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[a _{n}=5\left( 4 \right)^{n1}\] \[a _{n1}=5\left( 4 \right)^{n11}=5\left( 4 \right)^{n1}\left( 4 \right)^{1}=\frac{ 1 }{ 4 } a {n}\] \[a _{n}=4a _{n1}\]
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