How do I convert y-5=-2(x+1)^2 to intercept form? The standard form is y=-2x^2-4x+3!

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How do I convert y-5=-2(x+1)^2 to intercept form? The standard form is y=-2x^2-4x+3!

Mathematics
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You might want to check my work over, but if you are trying to get the equation into slope intercept y= mx+b form then these are the steps. First, multiply the quadratic in the parentheses; y-5=-2(x^2+1). then multiply -2; y-5=-2x^2-2. Then add 5 over; y=2x^2+3. I will check this through, but this is my best for now
oops! i meant intercept form as in y=(x-r1)(x-r2)
I tried factoring, but you can't factor it. and I tried the quadratic equation but i'm getting -1+- 2sqrt10 which isn't right i think

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If it is not factorizable, then I think you can't convert that equation into Intercept Form..
really? idk i know the intercepts are -2.581 an .581 though
and*
I mean you can't convert, but the person who knows how to convert, that person can convert. :P
Okay, let me try if I am that person or not.. :)
Add 5 both sides first to separate \(y\)...
\(y = -2(x^2 + 1 + 2x) + 5 \implies y = -2x^2 - 4x+ 3\)
Let us go with Quadratic Formula for a moment: \[x_{1,2} = \frac{4 \pm 2\sqrt{10}}{-4} \\ x_{1,2} = -1 \mp \frac{\sqrt{10}}{2}\]
So, yes you are right, you got the two intercepts right..
So: \(y = (x - 0.581)(x + 2.581)\)
ohh i thought i was wrong haha okay thanks:)

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