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Destinyyyy
 one year ago
Graph..
Destinyyyy
 one year ago
Graph..

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y=2x/1 8 y=2x/1 8

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2Is it just graphing 2x+y=8 4x+2y=16 ? did you put it in y=mx+b form first?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes I did.. My graph only goes to 6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does you graph only goes to \(6\) in one axis or both axes? Just plug in \(x\) values that are small, but still large enough that you can graph the lines.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes it only goes to 6.. Huh?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got the same line for both equations..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then just graph a /single/ line? When two lines overlay each other in a system of equations, it means there are infinite solutions.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2original 2x+y=8 4x+2y=16 y=mx+b form y=2x8 y=2x8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes I know that.. But it was only giving me options of x= a number and y= a number

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2for some reason I got the lines to be perpendicular when I graphed y=2x8 and y=2x8

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2maybe we have to solve for x and y using the graphing method

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You missed the negative on 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay.. How do I do that?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2no I didn't. 2x+y=8 4x+2y=16 is your original equation so I put it in y=mx+b form for the first equation 2x+y=8 y=2x8 for the second equation I need y to be just y... no digits next to it so I divided the whole thing by 2 4x+2y=16 2y=4x16 so dividing the whole equation by 2 y = 2x8

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so we can either graph y=2x8 and y=2x8 by letting x be any number, use elimination method, or find the y intercept which is set x = 0 for y = 2x8 and y=2x8 oh darn I did miss that negative the first time lol

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2< hasn't slept well in 3 days... mistakes are magic XD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok... graphing y = 2x8 and y =2x8 gave me a single line.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2maybe we just need to find intercepts after this... ? y = 2x8 and y=2x8 for x intercept let y = 0 for yintercept let x = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im leaving to take my final in less then 20 minutes.. last night I guessed on this problem

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2hmm... what was the question? could you give me the details?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2was it just graph or find intercepts or solve for x and y ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok then change the equations into y=mx+b form and graph letting x be any number you choose and solve for y so take y=2x8 for example if I let x = 1 then y = 2(1)8=18=10 so the point is (1,10)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2yeah if it just said to graph, and that's how you find points manually

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay.. Hopefully I remember that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for your help.
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