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Destinyyyy

  • one year ago

Graph..

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  1. Destinyyyy
    • one year ago
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    2x+y=-8 4x+2y=-16

  2. Destinyyyy
    • one year ago
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    y=-2x/1 -8 y=-2x/1 -8

  3. UsukiDoll
    • one year ago
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    Is it just graphing 2x+y=8 4x+2y=-16 ? did you put it in y=mx+b form first?

  4. Destinyyyy
    • one year ago
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    Yes I did.. My graph only goes to 6

  5. anonymous
    • one year ago
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    Does you graph only goes to \(6\) in one axis or both axes? Just plug in \(x\) values that are small, but still large enough that you can graph the lines.

  6. Destinyyyy
    • one year ago
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    Yes it only goes to 6.. Huh?

  7. Destinyyyy
    • one year ago
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    I got the same line for both equations..

  8. anonymous
    • one year ago
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    Then just graph a /single/ line? When two lines overlay each other in a system of equations, it means there are infinite solutions.

  9. UsukiDoll
    • one year ago
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    original 2x+y=-8 4x+2y=-16 y=mx+b form y=2x-8 y=-2x-8

  10. Destinyyyy
    • one year ago
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    Yes I know that.. But it was only giving me options of x= a number and y= a number

  11. UsukiDoll
    • one year ago
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    for some reason I got the lines to be perpendicular when I graphed y=2x-8 and y=-2x-8

  12. UsukiDoll
    • one year ago
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    maybe we have to solve for x and y using the graphing method

  13. Destinyyyy
    • one year ago
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    You missed the negative on 2

  14. Destinyyyy
    • one year ago
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    Okay.. How do I do that?

  15. UsukiDoll
    • one year ago
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    no I didn't. 2x+y=-8 4x+2y=-16 is your original equation so I put it in y=mx+b form for the first equation 2x+y=-8 y=-2x-8 for the second equation I need y to be just y... no digits next to it so I divided the whole thing by 2 4x+2y=-16 2y=-4x-16 so dividing the whole equation by 2 y = -2x-8

  16. UsukiDoll
    • one year ago
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    so we can either graph y=-2x-8 and y=-2x-8 by letting x be any number, use elimination method, or find the y intercept which is set x = 0 for y = -2x-8 and y=-2x-8 oh darn I did miss that negative the first time lol

  17. UsukiDoll
    • one year ago
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    <---- hasn't slept well in 3 days... mistakes are magic XD

  18. UsukiDoll
    • one year ago
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    ok... graphing y = -2x-8 and y =-2x-8 gave me a single line.

  19. UsukiDoll
    • one year ago
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    maybe we just need to find intercepts after this... ? y = -2x-8 and y=-2x-8 for x -intercept let y = 0 for y-intercept let x = 0

  20. Destinyyyy
    • one year ago
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    Im leaving to take my final in less then 20 minutes.. last night I guessed on this problem

  21. UsukiDoll
    • one year ago
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    hmm... what was the question? could you give me the details?

  22. UsukiDoll
    • one year ago
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    was it just graph or find intercepts or solve for x and y ?

  23. Destinyyyy
    • one year ago
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    It was graph

  24. UsukiDoll
    • one year ago
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    ok then change the equations into y=mx+b form and graph letting x be any number you choose and solve for y so take y=-2x-8 for example if I let x = 1 then y = -2(1)-8=-1-8=-10 so the point is (1,-10)

  25. Destinyyyy
    • one year ago
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    Thats it???

  26. UsukiDoll
    • one year ago
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    yeah if it just said to graph, and that's how you find points manually

  27. Destinyyyy
    • one year ago
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    Okay.. Hopefully I remember that

  28. Destinyyyy
    • one year ago
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    Thank you for your help.

  29. UsukiDoll
    • one year ago
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    you're welcome :)

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