anonymous
  • anonymous
Verify the identity. Cot[theta - pi/2] = -tan theta
Mathematics
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anonymous
  • anonymous
Verify the identity. Cot[theta - pi/2] = -tan theta
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
\[Cot \left( \theta - \frac{ \pi }{ 2 } \right) = -\tan \theta\]
anonymous
  • anonymous
anonymous
  • anonymous
I have to verify the identity and show my work

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imqwerty
  • imqwerty
we know that cot(-theta) = -cot(theta) we also know that cot(pi/2-theta) = tan(theta) multiply both sides by -1 we get -- -cot(pi/2-theta)=-tan(theta) we can write -cot(pi/2-theta) as cot(theta-pi/2) so nw we hav cot(theta-pi/2)= -tan(theta)
anonymous
  • anonymous
ok so where do i go from there? Im literally lost and I need to show my work
anonymous
  • anonymous
Or is that the answer? @imqwerty
anonymous
  • anonymous
Anyone?
imqwerty
  • imqwerty
wait :)
anonymous
  • anonymous
ok lol sorry
imqwerty
  • imqwerty
don't get lost :) that is the answer @EllenJaz17
anonymous
  • anonymous
oh ok, lol thank you!
imqwerty
  • imqwerty
ur welcome :) @EllenJaz17

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