## anonymous one year ago vance is designing a garden in the shape of an isosceles triangle. the base of the garden is 36 feet long. The function y = 18 tan theta models the height of the triangular garden. A. What is the height of the triangle when theta=45degrees? B. What is the height of the triangle when theta=55degrees? C. Vance is considering using either theta=45 degrees or theta=55degrees for his garden. Compare the areas of the two possible gardens. EXPLAIN how you found the areas. SHOW WORK FOR ALL PLEASE

1. anonymous

|dw:1437249873609:dw|

2. anonymous

@oleg3321

3. Oleg3321

ehhh idk sorry

4. anonymous

It's ok thank you :)

5. anonymous

@imqwerty do you know?

6. anonymous

@ganeshie8

7. anonymous

@Abhisar

8. anonymous

@nincompoop

9. anonymous

@kropot72

10. kropot72

Which part are you having trouble understanding?

11. anonymous

I dont know how to find any of the answers, that's why i need help and to show my work

12. kropot72

Do you know how to find the value of tan 45 degrees?

13. anonymous

No

14. kropot72

You can use the online calculator here to find the value of tan 45 degrees: http://web2.0calc.com/

15. anonymous

1

16. kropot72

Correct. Now what is tan 55 degrees?

17. anonymous

1.428

18. kropot72

Correct again. The area of a triangle is found from: $\large Area\ of\ \triangle=\frac{b}{2}\times\frac{h}{1}$ where b is the length of the base, and h is the vertical height. Or, in words, half the base times the vertical height. So the area of the triangle when theta is 45 degrees is found from $\large \frac{36}{2}\times(18\times1)=?\ ft^{2}$

19. anonymous

18ft

20. anonymous

@kropot72

21. kropot72

That is not the correct result for the calculation of the area. Here is the required calculation for the area of the triangle when theta is 45 degrees: $\large Area=\frac{36}{2}\times(18\times1)=you\ can\ calculate\ \ ft^{2}$

22. anonymous

324

23. kropot72

Here is the required calculation for the area of the triangle when theta is 55 degrees: $\large Area=\frac{36}{2}\times(18\times1.428)=(you\ can\ calculate)\ ft^{2}$

24. kropot72

Your result for the area when theta is 45 degrees is correct, except you need to add the units after the number.

25. anonymous

462.672

26. kropot72

Correct. But you need to put 462.672 sq. ft.

27. anonymous

So the answers are 324sq.ft and the other is 462.672sq.ft

28. kropot72

Yes, those are the correct areas for part C. Can you please post your results for part A and part B.

29. anonymous

how do i change the height for the degree and the theta

30. kropot72

You already used a calculator to find the values of tan 45 degrees and tan 55 degrees. So the height of the triangle when theta is 45 degrees is: h = 18 * 1 = ? And the height when theta is 55 degrees is: h = 18 * 1.428 = ?

31. anonymous

18ft and 25.7ft

32. anonymous

Thank you so much! I gave you a medal! I really appreciate it because I really needed the help!

33. kropot72

Correct.

34. kropot72

You're welcome :)