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anonymous

  • one year ago

vance is designing a garden in the shape of an isosceles triangle. the base of the garden is 36 feet long. The function y = 18 tan theta models the height of the triangular garden. A. What is the height of the triangle when theta=45degrees? B. What is the height of the triangle when theta=55degrees? C. Vance is considering using either theta=45 degrees or theta=55degrees for his garden. Compare the areas of the two possible gardens. EXPLAIN how you found the areas. SHOW WORK FOR ALL PLEASE

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  1. anonymous
    • one year ago
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    |dw:1437249873609:dw|

  2. anonymous
    • one year ago
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    @oleg3321

  3. Oleg3321
    • one year ago
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    ehhh idk sorry

  4. anonymous
    • one year ago
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    It's ok thank you :)

  5. anonymous
    • one year ago
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    @imqwerty do you know?

  6. anonymous
    • one year ago
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    @ganeshie8

  7. anonymous
    • one year ago
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    @Abhisar

  8. anonymous
    • one year ago
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    @nincompoop

  9. anonymous
    • one year ago
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    @kropot72

  10. kropot72
    • one year ago
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    Which part are you having trouble understanding?

  11. anonymous
    • one year ago
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    I dont know how to find any of the answers, that's why i need help and to show my work

  12. kropot72
    • one year ago
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    Do you know how to find the value of tan 45 degrees?

  13. anonymous
    • one year ago
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    No

  14. kropot72
    • one year ago
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    You can use the online calculator here to find the value of tan 45 degrees: http://web2.0calc.com/

  15. anonymous
    • one year ago
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    1

  16. kropot72
    • one year ago
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    Correct. Now what is tan 55 degrees?

  17. anonymous
    • one year ago
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    1.428

  18. kropot72
    • one year ago
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    Correct again. The area of a triangle is found from: \[\large Area\ of\ \triangle=\frac{b}{2}\times\frac{h}{1}\] where b is the length of the base, and h is the vertical height. Or, in words, half the base times the vertical height. So the area of the triangle when theta is 45 degrees is found from \[\large \frac{36}{2}\times(18\times1)=?\ ft^{2}\]

  19. anonymous
    • one year ago
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    18ft

  20. anonymous
    • one year ago
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    @kropot72

  21. kropot72
    • one year ago
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    That is not the correct result for the calculation of the area. Here is the required calculation for the area of the triangle when theta is 45 degrees: \[\large Area=\frac{36}{2}\times(18\times1)=you\ can\ calculate\ \ ft^{2}\]

  22. anonymous
    • one year ago
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    324

  23. kropot72
    • one year ago
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    Here is the required calculation for the area of the triangle when theta is 55 degrees: \[\large Area=\frac{36}{2}\times(18\times1.428)=(you\ can\ calculate)\ ft^{2}\]

  24. kropot72
    • one year ago
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    Your result for the area when theta is 45 degrees is correct, except you need to add the units after the number.

  25. anonymous
    • one year ago
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    462.672

  26. kropot72
    • one year ago
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    Correct. But you need to put 462.672 sq. ft.

  27. anonymous
    • one year ago
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    So the answers are 324sq.ft and the other is 462.672sq.ft

  28. kropot72
    • one year ago
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    Yes, those are the correct areas for part C. Can you please post your results for part A and part B.

  29. anonymous
    • one year ago
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    how do i change the height for the degree and the theta

  30. kropot72
    • one year ago
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    You already used a calculator to find the values of tan 45 degrees and tan 55 degrees. So the height of the triangle when theta is 45 degrees is: h = 18 * 1 = ? And the height when theta is 55 degrees is: h = 18 * 1.428 = ?

  31. anonymous
    • one year ago
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    18ft and 25.7ft

  32. anonymous
    • one year ago
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    Thank you so much! I gave you a medal! I really appreciate it because I really needed the help!

  33. kropot72
    • one year ago
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    Correct.

  34. kropot72
    • one year ago
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    You're welcome :)

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