vance is designing a garden in the shape of an isosceles triangle. the base of the garden is 36 feet long. The function y = 18 tan theta models the height of the triangular garden.
A. What is the height of the triangle when theta=45degrees?
B. What is the height of the triangle when theta=55degrees?
C. Vance is considering using either theta=45 degrees or theta=55degrees for his garden. Compare the areas of the two possible gardens. EXPLAIN how you found the areas.
SHOW WORK FOR ALL PLEASE

- anonymous

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- schrodinger

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- anonymous

|dw:1437249873609:dw|

- anonymous

@oleg3321

- oleg3321

ehhh idk sorry

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## More answers

- anonymous

It's ok thank you :)

- anonymous

@imqwerty do you know?

- anonymous

@ganeshie8

- anonymous

@Abhisar

- anonymous

@nincompoop

- anonymous

@kropot72

- kropot72

Which part are you having trouble understanding?

- anonymous

I dont know how to find any of the answers, that's why i need help and to show my work

- kropot72

Do you know how to find the value of tan 45 degrees?

- anonymous

No

- kropot72

You can use the online calculator here to find the value of tan 45 degrees:
http://web2.0calc.com/

- anonymous

1

- kropot72

Correct. Now what is tan 55 degrees?

- anonymous

1.428

- kropot72

Correct again.
The area of a triangle is found from:
\[\large Area\ of\ \triangle=\frac{b}{2}\times\frac{h}{1}\]
where b is the length of the base, and h is the vertical height.
Or, in words, half the base times the vertical height.
So the area of the triangle when theta is 45 degrees is found from
\[\large \frac{36}{2}\times(18\times1)=?\ ft^{2}\]

- anonymous

18ft

- anonymous

@kropot72

- kropot72

That is not the correct result for the calculation of the area. Here is the required calculation for the area of the triangle when theta is 45 degrees:
\[\large Area=\frac{36}{2}\times(18\times1)=you\ can\ calculate\ \ ft^{2}\]

- anonymous

324

- kropot72

Here is the required calculation for the area of the triangle when theta is 55 degrees:
\[\large Area=\frac{36}{2}\times(18\times1.428)=(you\ can\ calculate)\ ft^{2}\]

- kropot72

Your result for the area when theta is 45 degrees is correct, except you need to add the units after the number.

- anonymous

462.672

- kropot72

Correct. But you need to put 462.672 sq. ft.

- anonymous

So the answers are 324sq.ft
and the other is 462.672sq.ft

- kropot72

Yes, those are the correct areas for part C.
Can you please post your results for part A and part B.

- anonymous

how do i change the height for the degree and the theta

- kropot72

You already used a calculator to find the values of tan 45 degrees and tan 55 degrees.
So the height of the triangle when theta is 45 degrees is:
h = 18 * 1 = ?
And the height when theta is 55 degrees is:
h = 18 * 1.428 = ?

- anonymous

18ft and 25.7ft

- anonymous

Thank you so much! I gave you a medal! I really appreciate it because I really needed the help!

- kropot72

Correct.

- kropot72

You're welcome :)

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