anonymous
  • anonymous
q
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Michele_Laino
  • Michele_Laino
here we have to apply the total momentum conservation law
Michele_Laino
  • Michele_Laino
here is the situation described in your problem: |dw:1437247150772:dw|
Michele_Laino
  • Michele_Laino
if, after collision the two carts are attached together, then we can write this equation: \[\Large 2m{v_0} = \left( {m + 2m} \right)u\] where u is the final velocity

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Michele_Laino
  • Michele_Laino
and v_0=5 m/sec
Michele_Laino
  • Michele_Laino
so after a simplification, we get: \[\Large u = \frac{2}{3}{v_0} = ...?\]
Michele_Laino
  • Michele_Laino
more explanation: the total momentum of our system before collision is: \[\Large 2m{v_0}\] whereas the total momentum of our system, after collision is: \[\Large \left( {m + 2m} \right)u\] those momentum have to be equal each other
Michele_Laino
  • Michele_Laino
|dw:1437247606502:dw|
Michele_Laino
  • Michele_Laino
that's right! u=3.33 m/sec
Michele_Laino
  • Michele_Laino
where are you confused?
Michele_Laino
  • Michele_Laino
thanks! :)

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