A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
q
anonymous
 one year ago
q

This Question is Closed

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we have to apply the total momentum conservation law

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here is the situation described in your problem: dw:1437247150772:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1if, after collision the two carts are attached together, then we can write this equation: \[\Large 2m{v_0} = \left( {m + 2m} \right)u\] where u is the final velocity

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so after a simplification, we get: \[\Large u = \frac{2}{3}{v_0} = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1more explanation: the total momentum of our system before collision is: \[\Large 2m{v_0}\] whereas the total momentum of our system, after collision is: \[\Large \left( {m + 2m} \right)u\] those momentum have to be equal each other

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437247606502:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1that's right! u=3.33 m/sec

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1where are you confused?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.