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anonymous

  • one year ago

Consider the functions f(x) = 2x + 1 and g(x) = x2 − 10. What is the value of f[g(3)]? 39 −3 −7 -1

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  1. nincompoop
    • one year ago
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    you start from the inside then work your way through outside

  2. nincompoop
    • one year ago
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    first, solve g(x) since you are being asked to solve g(3) in the innermost function.

  3. anonymous
    • one year ago
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    x^3-10?

  4. anonymous
    • one year ago
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    -10?

  5. anonymous
    • one year ago
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    @pooja195

  6. Nnesha
    • one year ago
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    g(3) here x =3 so replace x by 3 not the exponent...

  7. anonymous
    • one year ago
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    so (3)-10?

  8. Nnesha
    • one year ago
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    and where is exponent 2 ??

  9. anonymous
    • one year ago
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    (3)^2-10?

  10. Nnesha
    • one year ago
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    \[\huge\rm g(\color{reD}{x}) = \color{red}{x}^2 -10\]

  11. Nnesha
    • one year ago
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    yes right!

  12. Nnesha
    • one year ago
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    and then substitute g(3) into f(x) function

  13. anonymous
    • one year ago
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    yikes, idk how

  14. Nnesha
    • one year ago
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    so what is g(3) =??

  15. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @lealealea222 (3)^2-10? \(\color{blue}{\text{End of Quote}}\) =what ?

  16. anonymous
    • one year ago
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    -1

  17. nincompoop
    • one year ago
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    so what is g(3) ?

  18. anonymous
    • one year ago
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    i think -1

  19. nincompoop
    • one year ago
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    okay now use f(x) being that x is -1

  20. anonymous
    • one year ago
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    is the answer -3 ?

  21. nincompoop
    • one year ago
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    look at this and tell me what you observe given: f(x) = 2x + 1 and g(x) = x2 − 10 \(f(x) = 2(x^2-10) +1 \)

  22. nincompoop
    • one year ago
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    tick tock tick tock lol

  23. anonymous
    • one year ago
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    man...

  24. anonymous
    • one year ago
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    idk haha

  25. nincompoop
    • one year ago
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    did you notice that I put the g(x) function into the f(x) function

  26. anonymous
    • one year ago
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    yes

  27. nincompoop
    • one year ago
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    look at it again

  28. anonymous
    • one year ago
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    you put them together

  29. anonymous
    • one year ago
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    i think its -3

  30. nincompoop
    • one year ago
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    how so what is \(2 \times (-1) \)

  31. anonymous
    • one year ago
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    -2x

  32. nincompoop
    • one year ago
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    |dw:1437249964034:dw|

  33. nincompoop
    • one year ago
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    it's not variable x, but the multiplication operation

  34. nincompoop
    • one year ago
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    use the number line I drew and place where -2 is

  35. anonymous
    • one year ago
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    oh ok let me do that again

  36. anonymous
    • one year ago
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    -2

  37. nincompoop
    • one year ago
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    use the number line I drew and place where -2 is

  38. nincompoop
    • one year ago
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    click the pencil icon on the upper right hand corner of my drawing so you can use it

  39. anonymous
    • one year ago
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    |dw:1437250193058:dw| ?

  40. nincompoop
    • one year ago
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    when you are adding, do you move the point to the left towards the negative infinity or to the right towards the positive infinity?

  41. anonymous
    • one year ago
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    toward the right

  42. anonymous
    • one year ago
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    toward the right

  43. anonymous
    • one year ago
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    ?

  44. anonymous
    • one year ago
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    i gtg

  45. nincompoop
    • one year ago
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    CORRECT SO WHAT HAPPENS FROM -2 WHERE WILL IT IF YOU +1

  46. anonymous
    • one year ago
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    -1

  47. anonymous
    • one year ago
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    THAMLS

  48. anonymous
    • one year ago
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    thats thankyou ^

  49. anonymous
    • one year ago
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    i just turned it in, i got it right

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