anonymous
  • anonymous
Consider the functions f(x) = 2x + 1 and g(x) = x2 − 10. What is the value of f[g(3)]? 39 −3 −7 -1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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nincompoop
  • nincompoop
you start from the inside then work your way through outside
nincompoop
  • nincompoop
first, solve g(x) since you are being asked to solve g(3) in the innermost function.
anonymous
  • anonymous
x^3-10?

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More answers

anonymous
  • anonymous
-10?
anonymous
  • anonymous
@pooja195
Nnesha
  • Nnesha
g(3) here x =3 so replace x by 3 not the exponent...
anonymous
  • anonymous
so (3)-10?
Nnesha
  • Nnesha
and where is exponent 2 ??
anonymous
  • anonymous
(3)^2-10?
Nnesha
  • Nnesha
\[\huge\rm g(\color{reD}{x}) = \color{red}{x}^2 -10\]
Nnesha
  • Nnesha
yes right!
Nnesha
  • Nnesha
and then substitute g(3) into f(x) function
anonymous
  • anonymous
yikes, idk how
Nnesha
  • Nnesha
so what is g(3) =??
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @lealealea222 (3)^2-10? \(\color{blue}{\text{End of Quote}}\) =what ?
anonymous
  • anonymous
-1
nincompoop
  • nincompoop
so what is g(3) ?
anonymous
  • anonymous
i think -1
nincompoop
  • nincompoop
okay now use f(x) being that x is -1
anonymous
  • anonymous
is the answer -3 ?
nincompoop
  • nincompoop
look at this and tell me what you observe given: f(x) = 2x + 1 and g(x) = x2 − 10 \(f(x) = 2(x^2-10) +1 \)
nincompoop
  • nincompoop
tick tock tick tock lol
anonymous
  • anonymous
man...
anonymous
  • anonymous
idk haha
nincompoop
  • nincompoop
did you notice that I put the g(x) function into the f(x) function
anonymous
  • anonymous
yes
nincompoop
  • nincompoop
look at it again
anonymous
  • anonymous
you put them together
anonymous
  • anonymous
i think its -3
nincompoop
  • nincompoop
how so what is \(2 \times (-1) \)
anonymous
  • anonymous
-2x
nincompoop
  • nincompoop
|dw:1437249964034:dw|
nincompoop
  • nincompoop
it's not variable x, but the multiplication operation
nincompoop
  • nincompoop
use the number line I drew and place where -2 is
anonymous
  • anonymous
oh ok let me do that again
anonymous
  • anonymous
-2
nincompoop
  • nincompoop
use the number line I drew and place where -2 is
nincompoop
  • nincompoop
click the pencil icon on the upper right hand corner of my drawing so you can use it
anonymous
  • anonymous
|dw:1437250193058:dw| ?
nincompoop
  • nincompoop
when you are adding, do you move the point to the left towards the negative infinity or to the right towards the positive infinity?
anonymous
  • anonymous
toward the right
anonymous
  • anonymous
toward the right
anonymous
  • anonymous
?
anonymous
  • anonymous
i gtg
nincompoop
  • nincompoop
CORRECT SO WHAT HAPPENS FROM -2 WHERE WILL IT IF YOU +1
anonymous
  • anonymous
-1
anonymous
  • anonymous
THAMLS
anonymous
  • anonymous
thats thankyou ^
anonymous
  • anonymous
i just turned it in, i got it right

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