A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Verify the identity. Justify each step. (PLEASE SHOW YOUR WORK)

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{ \sec \theta }{ \csc \theta - \cot \theta } - \frac{ \sec \theta }{ \csc \theta +\cot \theta } = 2 \csc \theta \]

  2. imqwerty
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    1st talke lcm and write the equation

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know how to do any of this

  4. imqwerty
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    What is the LCM of 1/2 and 1/3

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what does lcm mean?

  6. imqwerty
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Least common multiple

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2 and 3?

  8. welshfella
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    LCM is csc^2 O - cot^2O

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok than what

  10. imqwerty
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    After taking the lcm we get the common denominator nd then we can do addition nd subtraction in the numerators.

  11. welshfella
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    making it one fraction we get secO(csc^O + cot^2O) - secO(csc^2O - cot^2O) ----------------------------------------- csc^2 O - cot^2O = 2 secO cot^2O ----------- csc^2 O - cot^2O

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok than what?

  13. imqwerty
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    After this ^ step convert all values in tems of sin and cos

  14. welshfella
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    now csc^2 O = 1 + cot^2 O so the denominator = 1 so we are left with 2 sec O cot^2 O

  15. welshfella
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hmm might have slipped up somewhere cant get 2 csc O from that...

  16. welshfella
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea i see where i went wrong when making it into one fraction its ecO(cscO + cot O) - secO(csc O - cot O) ---------------------------------- csc^2 O - cot^2O

  17. welshfella
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    = 2sec O cot O = 2 *1 /cos O * ccos O / sin O = 2 csc O

  18. welshfella
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the denominator csc^2 O - cot^2O = 1 because csc^2 O = 1 + cot^2 O substituting;- 1 + cot^2 O - cot^2 O = 1

  19. LynFran
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    |dw:1437256289490:dw||dw:1437257039901:dw|

  20. welshfella
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea - good work LynFran

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So the answer is 2csctheta

  22. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @LynFran

  23. LynFran
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    yes when proving identities, whats on the left side of the equation must equals to the right side...

  24. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sweet thank you!

  25. LynFran
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    welcome

  26. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.