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Unofficialllyy

  • one year ago

I need help with this geometry question. I will fan and medal.

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  1. Unofficialllyy
    • one year ago
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    The main tank has a radius of 70 feet. What is the volume of the quarter-sphere sized tank? Round your answer to the nearest whole number. You must explain your answer using words, and you must show all work and calculations to receive credit.

  2. Unofficialllyy
    • one year ago
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    I know that I have to use the formula for volume of a sphere, and then once I get the volume I multiply it by 4, right? So I have written down: \[V=\frac{ 4 }{ 3 } \Pi r^3\] Then I plug in 70 for r: \[V=\frac{ 4 }{ 3 } \Pi(70)^3\] Is this correct so far?

  3. Unofficialllyy
    • one year ago
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    @welshfella could you see if you could help? :)

  4. Unofficialllyy
    • one year ago
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    @Loser66 ?

  5. Loser66
    • one year ago
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    why multiple by 4? the quarter sphere is 1/4 of the sphere. Not 4x Volume of the sphere.

  6. Unofficialllyy
    • one year ago
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    Or divide by 4? I dont know

  7. Loser66
    • one year ago
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    \(\div 4\)

  8. Unofficialllyy
    • one year ago
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    But am I right so far with what I have? After I got \[V=\frac{ 3 }{ 4} \Pi (70)^3\] I don't know how to solve this.

  9. Loser66
    • one year ago
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    ha!! |dw:1437249945106:dw|

  10. Unofficialllyy
    • one year ago
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    But couldn't figure out the volume first and then divide by 4?

  11. Loser66
    • one year ago
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    Either way, you can find volume first and then take \(V\div 4\) Or, take it directly as what I showed. Both them give you the same answer

  12. Unofficialllyy
    • one year ago
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    Yeah but I need help with solving for the volume

  13. Loser66
    • one year ago
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    why? just replace r = 70 and you got it

  14. Unofficialllyy
    • one year ago
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    I know that part. I don't know where to start though.

  15. Loser66
    • one year ago
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    \(V =\dfrac{4}{3}\pi r^3= \dfrac{4}{3}* 3.1415* (70)^3\)

  16. Unofficialllyy
    • one year ago
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    So then I do 70^3 first right?

  17. Loser66
    • one year ago
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    put it into calculator, then divide the answer by 4

  18. Unofficialllyy
    • one year ago
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    I cant just use a calculator, I have to show all calculations

  19. anonymous
    • one year ago
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    yeah do 70^3 first

  20. Loser66
    • one year ago
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    ok!!

  21. Unofficialllyy
    • one year ago
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    Then I multiply pi and 343000?

  22. anonymous
    • one year ago
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    Technically, you can do the multiplication in any order that you want (70^3 can be re written into 70*70*70) I personally find it easier to do that first

  23. Unofficialllyy
    • one year ago
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    okay so now i have \[V=\frac{ 3 }{ 4} \Pi(343000)\]

  24. Unofficialllyy
    • one year ago
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    I mean 4/3

  25. anonymous
    • one year ago
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    yep thats right

  26. Unofficialllyy
    • one year ago
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    Then what?

  27. anonymous
    • one year ago
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    You can multiply it by either pi or 4/3

  28. Unofficialllyy
    • one year ago
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    So if I multiply it by pi I get \[V=\frac{ 4 }{ 3 }(343000\pi)\]

  29. anonymous
    • one year ago
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    yes. Then you would multiply that by 4/3 to get the total volume of the sphere

  30. Unofficialllyy
    • one year ago
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    In decimal form thats 1436755.04024173

  31. Unofficialllyy
    • one year ago
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    Then I divide that by 4 to get the volume of a quarter sphere correct?

  32. anonymous
    • one year ago
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    yep

  33. Unofficialllyy
    • one year ago
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    359188.76006043

  34. Unofficialllyy
    • one year ago
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    And it has to be rounded to the nearest whole number

  35. anonymous
    • one year ago
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    so you would take the tenths place and see if it is above or below 5

  36. Unofficialllyy
    • one year ago
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    Yes it is above

  37. anonymous
    • one year ago
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    5 and above, give it a shove, 4 and below leave it down low

  38. anonymous
    • one year ago
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    Thats how I remember weather to round up or down

  39. Unofficialllyy
    • one year ago
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    so it would be 359189?

  40. anonymous
    • one year ago
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    yep

  41. Unofficialllyy
    • one year ago
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    Thank you so much!!

  42. anonymous
    • one year ago
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    No problem :) give credit to @Loser66 too. They helped out in the beginning

  43. Unofficialllyy
    • one year ago
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    Yes they did, thank you as well @Loser66 !!

  44. Loser66
    • one year ago
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    I am ok, I have a bunch of medals, don't care !!

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