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anonymous

  • one year ago

Jake says that the function is defined at x = –1, x = 3, and x = 4. Yoe says that the function is undefined at those x values. Who is incorrect? Justify your reasoning.

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  1. anonymous
    • one year ago
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    @Michele_Laino

  2. anonymous
    • one year ago
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    f(x)=(x-1)(x+2)(x+4)/(x+1)(x-2)(x-4)

  3. anonymous
    • one year ago
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    do you understand the function I wrote or should I draw i?

  4. Michele_Laino
    • one year ago
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    from the text of your problem I can write this expression for function f(x): \[\Large f\left( x \right) = \frac{{\left( {x - 1} \right)\left( {x + 2} \right)\left( {x + 4} \right)}}{{\left( {x + 1} \right)\left( {x - 2} \right)\left( {x - 4} \right)}}\]

  5. Michele_Laino
    • one year ago
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    now we can not divide by zero, so we have to exclude those values of x, such that: \[\Large \begin{gathered} x + 1 = 0 \hfill \\ x - 2 = 0 \hfill \\ x - 4 = 0 \hfill \\ \end{gathered} \] in other words we have to be certain that the denominator is not equal to zero

  6. anonymous
    • one year ago
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    ok, i see

  7. Michele_Laino
    • one year ago
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    for example if I solve the first equation, I get: x=-1 so I have to exclude that value

  8. Michele_Laino
    • one year ago
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    If I solve the second equation, I get: x=2 again, I have to exclude the value x=2

  9. Michele_Laino
    • one year ago
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    similarly for third equation: x-4=0 which gives: x=4, and i have to exclude that value

  10. anonymous
    • one year ago
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    ok:) I understand

  11. Michele_Laino
    • one year ago
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    ok!

  12. anonymous
    • one year ago
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    So the answer would be? @Michele_Laino

  13. Michele_Laino
    • one year ago
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    Edward is right!

  14. anonymous
    • one year ago
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    ok:) Thanks!!!

  15. Michele_Laino
    • one year ago
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    :)

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