Jake says that the function is defined at x = –1, x = 3, and x = 4. Yoe says that the function is undefined at those x values. Who is incorrect? Justify your reasoning.

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Jake says that the function is defined at x = –1, x = 3, and x = 4. Yoe says that the function is undefined at those x values. Who is incorrect? Justify your reasoning.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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f(x)=(x-1)(x+2)(x+4)/(x+1)(x-2)(x-4)
do you understand the function I wrote or should I draw i?

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from the text of your problem I can write this expression for function f(x): \[\Large f\left( x \right) = \frac{{\left( {x - 1} \right)\left( {x + 2} \right)\left( {x + 4} \right)}}{{\left( {x + 1} \right)\left( {x - 2} \right)\left( {x - 4} \right)}}\]
now we can not divide by zero, so we have to exclude those values of x, such that: \[\Large \begin{gathered} x + 1 = 0 \hfill \\ x - 2 = 0 \hfill \\ x - 4 = 0 \hfill \\ \end{gathered} \] in other words we have to be certain that the denominator is not equal to zero
ok, i see
for example if I solve the first equation, I get: x=-1 so I have to exclude that value
If I solve the second equation, I get: x=2 again, I have to exclude the value x=2
similarly for third equation: x-4=0 which gives: x=4, and i have to exclude that value
ok:) I understand
ok!
So the answer would be? @Michele_Laino
Edward is right!
ok:) Thanks!!!
:)

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