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anonymous

  • one year ago

Find all solutions in the interval [0,2pi] (sinx)(cosx)=0

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  1. anonymous
    • one year ago
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    Hi any help is appreciated :)

  2. freckles
    • one year ago
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    if a*b=0 then a=0 or b=0 or both=0

  3. LynFran
    • one year ago
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    |dw:1437259221024:dw| can you do for cos now?

  4. anonymous
    • one year ago
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    Cosx=0 X= cos^-1 0 ...

  5. anonymous
    • one year ago
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    Sorry this isn't my strength. I'm quite confused 😓

  6. LynFran
    • one year ago
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    go on...whats cos-1(0)=?

  7. anonymous
    • one year ago
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    90?

  8. anonymous
    • one year ago
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    That's what it said when I input it in my calculator

  9. LynFran
    • one year ago
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    yes 90 degree which is \[\frac{ \pi }{ 2}\]radians

  10. anonymous
    • one year ago
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    Ok so 0 and pi/2 are the 2 answers?

  11. LynFran
    • one year ago
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    |dw:1437259779522:dw|

  12. anonymous
    • one year ago
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    Ok so 0, pi/2, pi and 3pi/2?

  13. LynFran
    • one year ago
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    |dw:1437259932984:dw|

  14. LynFran
    • one year ago
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    |dw:1437260051924:dw|

  15. anonymous
    • one year ago
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    Thank you :)

  16. LynFran
    • one year ago
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    welcome

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