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what is the formula for the area of a rectangle?
its length times the width so so assuming (2x + 7) is the length and (5x + 9) is the width, the expression would be A=(2x + 7)(5x + 9)
i got that for part A
they probably want you to expand it (FOIL if you learned that)
ive never learned that,no
did you learn how to multiply two binomials ?
yes i think so
want me to?
FOIL is to remember First 2x*5x Outer 2x*9 Inner 7*5x Last 7*9 or 10x^2 + 18x+35x+63 and finally 10x^2 +53x+63
yea thats what i got
is that part of Part A?
yes, that is part A. (They want you to show your work... I assume you did)
yay i got part a, so can you help with part B?
Degree is the biggest exponent classification is polynomial
so first degree binomial?
is that right?
\[ 10x^2 +53x+63 \] what is the biggest exponent (little number in the upper right)
oops, 2nd degree
i was looking at the the problem, not the solution for A=(2x + 7)(5x + 9) =10x^2 +53x+63
yes. all the suffices bi, tri, quad are Latin for 2, 3, 4 It helps to know your Latin FYI, the expression (2x + 7)(5x + 9) even if not multiplied out, is 2nd degree (or "quadratic" )
though we could not really call it trinomial if it's not multiplied out.
so what do we call it
part C is the same answer as the other problem, except use multiply instead of add or subtract.
You posted the answers: 2nd degree, trinomial
so for part c its (10x^2)(53x)(63) ?
for part B, you might want to also call it quadratic (just in case that is what they are expecting) for part C, the idea is if you multiply two polynomials, the answer will be a polynomial in part A, you do that, and the answer was a polynomial
do i put that for part c?
in your own words.
ok thankyou! Can you check my answers from the other question??
Side 1: 3x2 − 4x − 1 Side 2: 4x − x2 + 5 The perimeter of the triangle is 5x3 − 2x2 + 3x − 8. Part A: What is the total length of the two sides, 1 and 2, of the triangle? (4 points) Part B: What is the length of the third side of the triangle? (4 points) Part C: Do the answers for Part A and Part B show that the polynomials are closed under addition and subtraction? Justify your answer. (2 points) Part A: The total length is 3x^2-x^2,which makes 2x^2+4 Part B: 4-12=-8 Part C:Part a and b both started with polynomials, and had a polynomial as an answer. So its showing that polynomials are closed under subtraction/addition.
Part A you say ***The total length is 3x^2-x^2*** that leaves out quite a bit. if you add two polynomials, you have to put in the entire polynomial , not just the cute terms you like
3x2 − 4x − 1 + 4x − x2 + 5
so do i say "3x2 − 4x − 1+4x − x2 + 5=3x^2-x^2" ??
the left side is good. the right side should be the "simplified" version for example you have 3 x^2 terms take away 1 x^2 term I would combine those to get just 2x^2 (not "3x^2-x^2" because that is not simplified) then do -4x + 4x (easy I hope?!) then do -1+5
yes. You had the correct answer, but how you got the answer looked dubious.
Part B I thought we did this. perimeter - (two sides) = 3rd side you should be showing polynomial (perimeter) - polynomial (from part A) = polynomial (answer)
You got the answer in the other post.
ill look back at it brb
no wait thats A 5x3−4x2+3x−12 ?
first write down the polynomial for the perimeter then minus sign then (in parens) the polynomial from part A
then = and finally the answer 5x3−4x2+3x−12
5x3 − 2x2 + 3x − 8-(2x^2+4)= 5x3−4x2+3x−12?
part C is ok
good job. But if concentrate , it would go faster. We had to do that question twice.