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mathmath333
 one year ago
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mathmath333
 one year ago
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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{if}\ x^2+ax+b\ \text{leaves same remainder } 5\hspace{.33em}\\~\\ & \normalsize \text{when divided by}\ (x1)\ \text{or}\ (x+1)\hspace{.33em}\\~\\ & \normalsize \text{then the values of}\ a\ \text{and}\ b\ \text{are}\hspace{.33em}\\~\\ \end{align}}\)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x)=x^2+ax+b \\ f(1)=1^2+a(1)+b=5 \\ f(1)=(1)^2+a(1)+b=5\]

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0is \(f(1)\) for \((x1)\)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1f(1) is for dividing by x(1)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0what is this method called

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{P(x)}{x1}=Q(x)+\frac{R}{x1} \\ P(x)=Q(x)(x1)+R \\ \text{ plugin 1} \\ P(1)=Q(1)(11)+R \\ P(1)=Q(1)(0)+R \\ P(1)=0+R \\ P(1)=R\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1and we can then divide P(x) by (x+1) and plug in 1 and you see we will get R there too

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0the previus one is easy
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