anonymous
  • anonymous
Please Help meeeeeeeee I'm meltingggggg!!!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[(3^{-1}-2^{-1})^{-1}\]
DecentNabeel
  • DecentNabeel
1/(1/3 -1/2) \[\left(-2^{-1}+3^{-1}\right)^{-1}=-6\]
anonymous
  • anonymous
ya, i did it on my calc and its -6

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
|dw:1437259855827:dw|
anonymous
  • anonymous
is that the way to do it? I know there are other ways to do it but is this viable?
anonymous
  • anonymous
\[\left( 3^{-1}-2^{-1} \right)^{-1}=\left( \frac{ 1 }{ 3^1 }-\frac{ 1 }{ 2^1 } \right)^{-1}\] \[=\left( \frac{ 2-3 }{ 6 } \right)^{-1}=\left( \frac{ -1 }{ 6 } \right)^{-1}=\frac{ \left( -1 \right)^{-1} }{ \left( 6 \right)^{-1} }=\frac{ 6^1 }{ \left( -1 \right) }\]=-6
anonymous
  • anonymous
how about the way i did it? is that okay too?
anonymous
  • anonymous
????
anonymous
  • anonymous
no
anonymous
  • anonymous
o...
anonymous
  • anonymous
\[x^a=\frac{ 1 }{ x ^{-a} }~and~viceverse\]
DecentNabeel
  • DecentNabeel
\[\mathrm{Apply\:exponent\:rule}:\quad \:a^{-1}=\frac{1}{a}\] \[=\left(-\frac{1}{2}+\frac{1}{3}\right)^{-1}\]
DecentNabeel
  • DecentNabeel
\[\left(-\frac{1}{2}+\frac{1}{3}\right)^{-1}=\frac{1}{-\frac{1}{2}+\frac{1}{3}}\] \[\mathrm{Combine\:the\:fractions\:using\:the\:LCD}:\quad -\frac{1}{2}+\frac{1}{3}=\frac{2-3}{6}\]
DecentNabeel
  • DecentNabeel
\[=\frac{1}{-\frac{1}{6}}\] =-6
DecentNabeel
  • DecentNabeel
are you understand @yomamabf

Looking for something else?

Not the answer you are looking for? Search for more explanations.