## Naudiapie one year ago What is the equation of a circle that passes through point J(6, 4) and has center K (1, -8).

1. Naudiapie

2. Mertsj

Use the distance formula to calculate the length of the radius.

3. Naudiapie

um can you show me? like give me an example of how i would set it up and everything

4. Naudiapie

i don't know :(

5. Mertsj

What is the distance formula?

6. Naudiapie

D= sr(x2-x1)^2 + (y2-y1)^2

7. Mertsj

Now plug in: the two points are: (6,4) and (1,-8)

8. Mertsj

So x2=8 x1=6 y2=-8 y1=4

9. Naudiapie

x= 8? wouldn't it be 1 though?

10. Naudiapie

where did you get 2 8's at, ugh, this is confusing well i did 6-1 = 5 and 4 - 8 = -4 . ... so 5 - 4 = 1 , is 1 right?

11. Mertsj

Sorry. x2=1

12. Naudiapie

oh wait i forget to square them

13. Naudiapie

so it would be like 20 - 16?

14. Naudiapie

which is 4 and the square root of 4 is 2 ... idk :(

15. Mertsj

|dw:1437270786863:dw|

16. Mertsj

$d=\sqrt{(1-6)^2+(-8-4)^2}=\sqrt{(-5)^2+(-12)^2}=$

17. Mertsj

Now you finish it.

18. Naudiapie

169

19. Naudiapie

13

20. Naudiapie

thank you

21. Mertsj

Can you finish the problem now that you know the radius is 13?

22. Naudiapie

yes thank you lots :o

23. Mertsj

yw