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anonymous

  • one year ago

What is the arc length of a circle that has a 6-inch radius and a central angle that is 65 degrees? Use 3.14 for π and round your answer to the nearest hundredth. - 0.65 inch - 1.13 inches - 6.80 inches - 390.01 inches

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  1. anonymous
    • one year ago
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    @Mertsj Can you help me please or ask anyone to?

  2. anonymous
    • one year ago
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    @wolf1728

  3. Mertsj
    • one year ago
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    65 degrees is 65/360 of the entire circle. The length of the entire circle is 2 pi r. Find 2 pi r and multiply it by 65/360

  4. wolf1728
    • one year ago
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    6-inch radius central angle = 65 degrees Circumference = 2*PI*6 Circumference = 37.70 The arc would be (65/360) of the circle or 0.18055556 0.18055556 * 6 = 1.083333 Rounding pi to 3.14 would make the answer 1.08

  5. anonymous
    • one year ago
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    The closest answer would 1.13 because it is closer

  6. anonymous
    • one year ago
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    Can you help with another

  7. wolf1728
    • one year ago
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    Wait I messed up answer is 0.18055556 * 37.70 = 6.806784 SORRY !!!

  8. anonymous
    • one year ago
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    oh thank you lol

  9. anonymous
    • one year ago
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    can you help with another

  10. wolf1728
    • one year ago
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    Here's a calcualtor to check it http://www.1728.org/radians.htm And I'll help with another

  11. anonymous
    • one year ago
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    The point (−3, 1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? Make sure to show all work.

  12. wolf1728
    • one year ago
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    I don't exactly know know specifically what they mean by terminal side, standard position. MAYBE it's that angle starts at (0,0)?

  13. anonymous
    • one year ago
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    Hmmm.....

  14. Mertsj
    • one year ago
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    |dw:1437271081791:dw|

  15. Mertsj
    • one year ago
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    \[\sin =\frac{o}{h};\cos =\frac{a}{h};\tan =\frac{o}{a}\]

  16. wolf1728
    • one year ago
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    That's what I thought Mertsj (the graphic)

  17. Mertsj
    • one year ago
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    Remember, sin is positive in Quadrant II cos and tan are negative in Quadrant II

  18. anonymous
    • one year ago
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    I am lost

  19. Mertsj
    • one year ago
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    What is the definition of the sine of an acute angle of a right triangle?

  20. anonymous
    • one year ago
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    sin

  21. anonymous
    • one year ago
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    sin \[\sin \]

  22. anonymous
    • one year ago
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    Sorry can't make the sign with the os

  23. Mertsj
    • one year ago
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    Just finish this: \[\sin x = \]

  24. Mertsj
    • one year ago
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    Use these terms: side opposite, side adjacent, or hypotenuse

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