anonymous
  • anonymous
What is the arc length of a circle that has a 6-inch radius and a central angle that is 65 degrees? Use 3.14 for π and round your answer to the nearest hundredth. - 0.65 inch - 1.13 inches - 6.80 inches - 390.01 inches
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@Mertsj Can you help me please or ask anyone to?
anonymous
  • anonymous
@wolf1728
Mertsj
  • Mertsj
65 degrees is 65/360 of the entire circle. The length of the entire circle is 2 pi r. Find 2 pi r and multiply it by 65/360

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wolf1728
  • wolf1728
6-inch radius central angle = 65 degrees Circumference = 2*PI*6 Circumference = 37.70 The arc would be (65/360) of the circle or 0.18055556 0.18055556 * 6 = 1.083333 Rounding pi to 3.14 would make the answer 1.08
anonymous
  • anonymous
The closest answer would 1.13 because it is closer
anonymous
  • anonymous
Can you help with another
wolf1728
  • wolf1728
Wait I messed up answer is 0.18055556 * 37.70 = 6.806784 SORRY !!!
anonymous
  • anonymous
oh thank you lol
anonymous
  • anonymous
can you help with another
wolf1728
  • wolf1728
Here's a calcualtor to check it http://www.1728.org/radians.htm And I'll help with another
anonymous
  • anonymous
The point (−3, 1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? Make sure to show all work.
wolf1728
  • wolf1728
I don't exactly know know specifically what they mean by terminal side, standard position. MAYBE it's that angle starts at (0,0)?
anonymous
  • anonymous
Hmmm.....
Mertsj
  • Mertsj
|dw:1437271081791:dw|
Mertsj
  • Mertsj
\[\sin =\frac{o}{h};\cos =\frac{a}{h};\tan =\frac{o}{a}\]
wolf1728
  • wolf1728
That's what I thought Mertsj (the graphic)
Mertsj
  • Mertsj
Remember, sin is positive in Quadrant II cos and tan are negative in Quadrant II
anonymous
  • anonymous
I am lost
Mertsj
  • Mertsj
What is the definition of the sine of an acute angle of a right triangle?
anonymous
  • anonymous
sin
anonymous
  • anonymous
sin \[\sin \]
anonymous
  • anonymous
Sorry can't make the sign with the os
Mertsj
  • Mertsj
Just finish this: \[\sin x = \]
Mertsj
  • Mertsj
Use these terms: side opposite, side adjacent, or hypotenuse

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