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"bisects" means splitting into two equal halves |dw:1437275619121:dw|
therefore the measures \(4x-25\) and \(2x+5\) are equal : \[4x-25 = 2x+5\] solve \(x\)

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Would I add the 4x and 2x and then the -25 and 5?
The goal here is to isolate \(x\), you start by adding 25 both sides so that that left hand side becoems simpler : \[4x-25+25 = 2x+5+25\] \[4x = 2x+30\]
Would I then subtract 2x from 4x?
Yes!
thank you! I'm not too smart lol
You're smart enough
\[4x = 2x+30\] subtract 2x both sides and get \[2x= 30\] divide 2 both sides \[x = 15\]
plug that in the earlier expression for angle
|dw:1437276247948:dw|

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