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anonymous
 one year ago
The value 2 is a lower bound for the zeros of the function shown below.
f(x)=4x^312x^2x+15
anonymous
 one year ago
The value 2 is a lower bound for the zeros of the function shown below. f(x)=4x^312x^2x+15

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1all positive values are upper bound all negative values are lower bound

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it false? I use synthetic division right? I got 4, 20, 39, 171

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1can you draw that synthetic division for me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437277905106:dw sorry it's kind of hard to read but i just realized i messed up earlier haha is it still false though?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because not everything is negative??

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x)=4x^312x^2x+15 \] is our function oh I see we use 2 for synthetic division

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437278252692:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so the first entry should go down dw:1437278300525:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1then we multiply 2 x 4

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437278367948:dw then use addition we should get 20

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1now 2 x 20 = 40 dw:1437278417562:dw and then we should have 39

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437278454846:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yup thats what i got too!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so now we can rewrite this the last part should be \[\frac{63}{x2} \] because 63 is the remainder

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1ok I'm going backwards in writing this since it's been a while

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1ack wrong sign \[4x^2 20x+39\frac{63}{x+2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would it be true or false?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1since 2 < 0 and the signs during the synthesis division alternate, we have a lower bound for real roots of the function.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh. i get it, thank you :)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1geez what is with my writing? I meant signs during the synthetic division alternate XD
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