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## Nick88888888 one year ago Write log base 3 of one-eighty-first equals negative 4 in exponential form. 3 raised to the negative one-fourth equals one-eighty-first 3 to the fourth equals one-eighty-first 3 to the negative fourth equals one-eighty-first negative fourth root of 3 equals one-eighty-first

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1. Nick88888888

|dw:1437283428833:dw|

2. Nick88888888

Would it be |dw:1437283641146:dw|

3. campbell_st

well your solution make sense since $\log_{3}(\frac{1}{81} = \log_{3}(3^{-4})$ use the log laws for indexes and $\log_{3}(3^{-4}) = -4\log_{3}(3)$ and you should know what $\log_{3}(3) =?$

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