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Which of the following pairs does not share the same empirical formula? C2H6 and C4H12 C3H6O3 and C2H4O2 C3H8O and CH2O C2H6 and CH4? Chemistry ASAP
I'll give medals anything just please help
watch this http://study.com/academy/lesson/the-activity-series-predicting-products-of-single-displacement-reactions.html
Okay so can we work through them? @richarddelfin
I'm thinking D for the first question and D for the last question
@jagat2713 @photon336 @rvc
Yes, your first question is D. Because Zn is less reactive than Ba. You can check it in the activity series list.
And the second?
So Zn will never replace Ba
If 4.0 miles of X and 4.0 moles of Ay react according to the hypothetical reaction below, how many miles of the excess reactant will be left over at the end of the reaction? 2X + 3Y ==> Xsub2Y sub 3 1.3 y left over 2.7 y leftover 1.3 x left over 2.7 x left over I'm thinking C but I'm not sure
In the second one you just have to simplify. a) C2H6 - C4H12 / They both come from the same empiric formula CH3 (see if i multiply CH3 by 2, i get the first formula and if do it by 4 i get the other one) b) C3H6O3 -C2H4O2 / Empiric formula for this pair is CH2O, 1st is multiplied by 3 and 2nd is multiplied by 2 Feel free to do the other one. Hint: U can't simplify 1 atom. Like i didnt keep reducing CH2O or CH3
Ok so D does not reduce right?
I don't think you're even trying. About your third question Indeed, 1.3 moles of X are left over, and Y is the limiting reactant, because if you wanted to react 4 mol of X you would need 6 mol of Y, which you dont have.
and i'd say there are 2 answers in #2, C and D
See this is why I'm confused
I'm Only allowed one
Which one is the better choice
Go for C, since they maybe made a mistake at D and typed C2H6 instead of C2H8.
I'll double check let me see
Your right! These are the choices. 1. C2H6 & C6H18 2. C3H6O3 & C2H4O2 3. C3H6 & CH4 4. CH2O & C3H6O3
I'm leaning toward d again am I right? @ricardodelfin
Please someone help with the second question I've been working on this exam since 8pm & this is my last question please help me w/ #2