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yamyam70

  • one year ago

I need help with these solve the inequality 0<3x + 2 <1

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  1. insa
    • one year ago
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    u can make two pairs out of that |dw:1437296021976:dw|

  2. insa
    • one year ago
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    can u solve it now?

  3. insa
    • one year ago
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    @yamyam70

  4. yamyam70
    • one year ago
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    -2/3 < x < -1/3

  5. yamyam70
    • one year ago
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    THANKS!

  6. UsukiDoll
    • one year ago
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    another method \[0<3x + 2 <1 \] subtract 2 all over the inequality \[0-2<3x + 2-2 <1 -2\] \[-2<3x <-1\] and then divide 3 all over the inequality \[\frac{-2}{3}<\frac{3}{3}x <\frac{-1}{3}\] \[\frac{-2}{3}<x <\frac{-1}{3}\]

  7. UsukiDoll
    • one year ago
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    @yamyam70 just for reference/information purposes. It's good to learn more than one valid method for solving a math problem as long as it doesn't break math rules :)

  8. yamyam70
    • one year ago
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    |dw:1437297811873:dw|

  9. yamyam70
    • one year ago
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    is that correct?

  10. UsukiDoll
    • one year ago
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    hmmm that inequality we had earlier shows that it's between -2/3 < x < -1/3 and it's an open circle. looks similar to your drawing, but let's try using a number line |dw:1437298046045:dw|

  11. yamyam70
    • one year ago
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    considering -2/3 = -0.666 -1/3 = 0.3333 hey thanks maybe ill just put my values for X the way you wrote it :) TY!

  12. UsukiDoll
    • one year ago
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    you're welcome :)

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