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  • one year ago

A) Convert the following expression to exponential form: log2 128 = k B) Using trial and error, find the correct value of k. Prove that your answer is correct. Ive done this so far A) if y= b^x, then x=logb y Log2 128= k ^Base ^exponent 2^k=128 B) 2^7=128

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  1. Nick88888888
    • one year ago
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    is A) correct? and how would i do B?

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