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anonymous
 one year ago
(y+3)^3+8 ? how to factor completely ?
anonymous
 one year ago
(y+3)^3+8 ? how to factor completely ?

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5sum of cubes formula \[(a+b)^3 =(a+b)(a^2ab+b^2) \] rewrite \[(y+3)^3=8\] as \[(y+3)^3=2^3\] so let a = y+3 and b = 2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5well the b portion is easy because if b = 2 then b^2 is ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5OH MAN! I GOT MY LATEX WRONG NUGH! \[\large (y+3)^3+ 8 \rightarrow = (y+3)^3+2^3 \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5but the sum of cubes formula is correct thank goodness.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5so if b = 2 what's b^2 = ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[\large (y+3)^3+ 8 \rightarrow (y+3)^3+2^3\] idk what's with me in the middle of the night

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5but yes b^2 = 4 because b = 2 2^2 = 4 woo.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[((y+3)+(2))^3 =((y+3)+2)((y+3)^22(y+3)+4)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(y+3+2) = (y+5) (_______)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5so we need to expand (y+3)^2 and distribute the 2 on y+3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(y+5)(y^2+9(y+3+2)+4) ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5wait.. try expand this in parts expand \[(y+3)^2 \] and then distribute 2(y+3)

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1i didn't even say something :(

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1i ws here to help k..sry bye i won't interrupt u frm nw .

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5then distribute the 2 for 2(y+3)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5yes so now we can place them into our equation \[((y+3)+(2))^3 =((y+3)+2)((y+3)^22(y+3)+4) \] \[((y+3)+(2))^3 =(y+5)(y^2+3y+92y6+4) \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5then we can rearrange and combine like terms...

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[(y+5)(y^2+3y2y6+4+9)\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5so combine like terms in the super long equation what's 3y2y what's 6+4+9

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5cool so now we need to ... wow distribute \[(y+5)(y^2+y+7)\] so distribute the y throughout \[y^2+y+7\] like \[y(y^2+y+7)\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[(y^2(y)+y(y)+7(y))\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5do you know the exponent laws ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5excellent! now we do the same thing for the 5 \[(y+5)(y^2+y+7) \] so distribute 5 throughout \[y^2+y+7\] \[5(y^2+y+7)\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5so it's like 5 x y^2 5 x y 5 x 7

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5yeah! so now we combine like terms \[y^3+y^2+7y+5y^2+5y+35\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5_ something is wrong ... our middle terms are off.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5yeah but I'm double checking through a calculator and it claims that it's 9y^2+27y unless ... hey @Haseeb96 could you come over here and check this?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5oh nevermind.. wait let me think... our first term and last term is correct..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i hate factoring completely :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0bye :) i have lot to do :/

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5ok. I'll try and figure out what's up before I go sleep. Maybe we needed pascal's triangle/binomial theorem.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks for your time dude :)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5you're welcome. I'm gonna post the pascal's triangle version.. I see it clearer on how they got the middle term... another method is to exapand (y+3)^3 manually and add 8 but who wants to do that ? that's time consuming.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311220374:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5so from k = 0 to k = 3 ...

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311295892:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311393568:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311428990:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311489980:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311527971:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311547143:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311614971:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5@freckles wait don't go! I was using sum of cubes and the middle terms were wonky . What gives?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311655716:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311666239:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5ugh this thing is a troll x.x

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5y^3+9y^2+27y+35 ... should be it but the middle terms splash out when I did sum of cubes. So I'm doing Pascal's triangle / Binomial Theorem and that's working so far

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311833243:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.0\[(y+3)^3+8 \\ a^3+b^3=(a+b)(a^2ab+b^2) \\ a=y+3 \\ b=2 \\ a^2=(y+3)^2 \\ b^2=4 \\ a^3=(y+3)^3 \\ b^3=8 \\ \\ \text{ input into formula } \\ (y+3)^3+8=(y+3+2)([y+3]^2[y+3](2)+4) \\ (y+3)^3+8=(y+5)(y^2+6y+92y6+4) \\ \text{ combine like terms inside the second () }\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311848473:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311880098:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311906118:dw that should be 1 since everything cancels.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311933179:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.0I think I see what you did wrong

freckles
 one year ago
Best ResponseYou've already chosen the best response.0\[(y+3)^2=y^2+6y+9 \\ (y+3)^2 \neq y^2+3y+9\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437311941673:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5OMg x.x Not my night

freckles
 one year ago
Best ResponseYou've already chosen the best response.0it was probably just a typeo and you just never fixed and you forgot about it or whatever happens to me too

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437312099694:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5dw:1437312142306:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5\[ (y+5)(y^2+4y+7)\] \[y^3+4y^2+7y+5y^2+20y+35 = y^3+9y^2+27y+35\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5because (y+3)(y+3) = y^2+3x+3x+9 = y^2+6x+9 I must have overlooked it. so sum of cubes can be used after all.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.5@freckles I got it to work :)
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