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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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  2. kropot72
    • one year ago
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    Sorry, the table makes no sense to me.

  3. anonymous
    • one year ago
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    That's alright.... I think I got it anyways! Thanks for trying :D

  4. amistre64
    • one year ago
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    test of independence, is a chi squared test. if we view this 2x2 as a matrix, then the t.s. can be calculated as the square of the determinant, times n, divided by the product of the totals for each row/col a b | a+b c d | c+d ----------------- a+c b+d | n \[\chi^2=\frac{n|A|^2}{(a+b)(a+c)~(c+d)(b+d)}\]

  5. amistre64
    • one year ago
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    http://math.hws.edu/javamath/ryan/ChiSquare.html

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