Factor: x2 - 100

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Factor: x2 - 100

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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hint: (A^2-B^2) = (A+B)(A-B) x^2 - 100 = ?
yes, and `100=10²` as you probably know already.
difference of squares formula \[(a^2-b^2)=(a+b)(a-b) \]

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Other answers:

is it 1000? IDK
x² - 100 = x² - 10² = (you tell me)
O_O ok what's the square root of 100?
u won't get a number, you should get `(blank)(blank)`
find the square root of 100 and the square root of x^2
Okay, maybe I should do a different example?
ok
maybe what's 10 x 10 !?!
100
all right.. so the square root of 100 is 10 so we've found one piece of the solution
\[(a^2-10^2)=(a+10)(a-10)\]
ok
so all we need to do is find the square root of x^2
what?
or if you memorize the formula let a = x
formula?
\[(a^2-10^2)=(a+10)(a-10)\] we had x^2 - 100 earlier and our formula is \[(a^2-b^2)=(a+b)(a-b) \]
so if b was 10 what's our a?
wait what
i'm confused
Problem: Factor: p²-49. Solution: We are going to apply the difference of squares formula that states: `a²-b²=(a+b)(a-b)` My a² in this case is p², and b² is 49. So, what will my a and b be? if a² is in this case p², then a is in this case p (you know why, right?) if my b² is 49, then my b is 7 (because √49 = 7) So, we end up getting: `p² - 49 = (p + 7)(p - 7)` (and this is the answer) `~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~` `~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~` Additional note. if you expand it beckwards you can see why this formula works. \(\Large\color{black}{ \displaystyle ({\rm \color{blue}{b}}+{\rm \color{red}{a}})({\rm \color{blue}{b}}-{\rm \color{red}{a}})= }\) \(\Large\color{black}{ \displaystyle {\rm \color{blue}{b}}({\rm \color{blue}{b}}-{\rm \color{red}{a}})+{\rm \color{red}{a}}({\rm \color{blue}{b}}-{\rm \color{red}{a}})=}\) \(\Large\color{black}{ \displaystyle {\rm \color{blue}{b}}^2-{\rm \color{red}{a}}{\rm \color{blue}{b}}+{\rm \color{red}{a}}{\rm \color{blue}{b}}-{\rm \color{red}{a}}^2=}\) \(\Large\color{black}{ \displaystyle {\rm \color{blue}{b}}^2~\cancel{-{\rm \color{red}{a}}{\rm \color{blue}{b}}}~\cancel{+{\rm \color{red}{a}}{\rm \color{blue}{b}}}-{\rm \color{red}{a}}^2=}\) \(\Large\color{black}{ \displaystyle {\rm \color{blue}{b}}^2-{\rm \color{red}{a}}^2.}\) So we therefore have: \(\Large\color{black}{ \displaystyle {\rm \color{blue}{b}}^2-{\rm \color{red}{a}}^2=}\)\(\Large\color{black}{ \displaystyle ({\rm \color{blue}{b}}+{\rm \color{red}{a}})({\rm \color{blue}{b}}-{\rm \color{red}{a}}) }\)
backwards*
your question is x^2-100 and in the form of \[(a^2-b^2)=(a+b)(a-b) \] so we've figured out that 10 x 10 = 100 and the square root of 100 is 10
ok
so from the formula if b = 10, then what should be our a hint: it's a variable and it's from x^2-100
\[x^2-100 \rightarrow (a^2-10^2)=(a+10)(a-10)\]
difference of square\[\huge\rm a^2- b^2 =(a+b)(a-b)\] so just take square root of FIRST TERM nd SQUARE ROOT of 2nd term \[\large\rm \sqrt{a^2}-\sqrt{b^2} =(a+b)(a-b)\] |dw:1437313113030:dw| one parentheses with plus sign and one with negative done!
i'm back
can someone just give me the answer
hello
ello
There is no use in giving you the answer, and thus I (and hope others as well) will not handle the answer this way. We have attempted a number of good explanation and none worked (some people even gave the answer away but not 100%). You are either not reading our replies, or there is a lack of knowledge to do this problem in the first place. I will suggest to review the post and your math textbook..... good luckl

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