anonymous
  • anonymous
Eliminate the arbitrary constants. Any solutions. Problem is given by the picture.
Differential Equations
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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Haseeb96
  • Haseeb96
is there any choices?
Haseeb96
  • Haseeb96
Well, there is no any solution to eliminate those constants. Because both are different

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More answers

UsukiDoll
  • UsukiDoll
something's off. it's like the general solution for a second order ode with a repeated root.
UsukiDoll
  • UsukiDoll
well I can't stay up... I'm off to bed.
anonymous
  • anonymous
the book say the answer is y"-2y'+y=0 i do not know how to solve it.
anonymous
  • anonymous
but the problem is to eleminate the arbitrary constants which are c1 and c2.
imqwerty
  • imqwerty
all u have to do is differentiation :) hope this helps
anonymous
  • anonymous
but how? I am having trouble of iy, i know how to get the derivative but i do not know how to eliminate.
freckles
  • freckles
@njwild you keep saying you want to eliminate the arbitrary constants but you said the answer was a differential equation so it makes me think you want to work from y=c1e^x+c2xe^x to get y''-2y'+y=0 . But if you are looking for the constants than you initial conditions.
anonymous
  • anonymous
but how to solve it by a given problem to get the answer with solution.
imqwerty
  • imqwerty
can u find the value of y' and y' by differentiation??
anonymous
  • anonymous
after differentiation imqwerty , what is the steps of rliminating or the first to eliminate until last to get the answer
anonymous
  • anonymous
@imqwerty I get the y' and y" but i do not know what is the first to eliminate until last to get the answer.
imqwerty
  • imqwerty
wait m tellin :)
imqwerty
  • imqwerty
it would take too long to type btw heres the solution - https://www.youtube.com/watch?v=HIdKpnWb2Ws
imqwerty
  • imqwerty
nt exactly the same but it may help u
freckles
  • freckles
If you are trying to get the differential equation from the solution here is my explanation: \[y=c_1e^x+c_2xe^{x} \\ \text{ the } x \text{ next to the other } e^x \text{ tells us we have a repeated solution \to the } \\ \text{ I will call it the characteristic equation } \\ \text{ since the solution is } y=c_1e^{1 \cdot x}+c_2 xe^{1 \cdot x} \\ \text{ then the solution to the charateristic equation } is r=1 \\ r-1=0 \\ (r-1)^2=0 \text{ since the solution is repeated } \\ r^2-2r+1=0\] from here it should be easy to write the differential equation
freckles
  • freckles
but to figure out what the constants are you need conditions such as y(a)=b and y'(c)=d whatever a,b,c, and d are given as
freckles
  • freckles
other than that I have no idea what you mean by eliminate the arbitrary constants
UsukiDoll
  • UsukiDoll
@freckles that's what I had typed earlier because we had to look for the repeated root, but it was getting late and the asker drove me nuts, so I was erasing my posts before I logged off. Users should stop posting generic questions and add more details instead of one liners.
anonymous
  • anonymous
differentiate twice and then eliminate c1 and c2 from three equations.

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