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anonymous

  • one year ago

if sec(θ)= 5/3 and the terminal point determined by θ is in quadrant 4, then CHECK ALL THAT APPLIES A. cos (θ)=3/5 B. csc (θ)= 5/4 C. tan (θ)= 4/3 D. sin (θ) = -(2/5)

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  1. DanJS
    • one year ago
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    sec(theta) = 1 / cos(theta)

  2. anonymous
    • one year ago
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    what does that mean

  3. DanJS
    • one year ago
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    sec(theta) = 1 / cos(theta) = 5 / 3 solve for cos(theta)

  4. DanJS
    • one year ago
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    in quadrant 4, cos(theta) is positive

  5. DanJS
    • one year ago
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    ( x, y ) = ( cos(theta) , sin(theta) ) 4th quadrant, positive X value, positive cos value

  6. anonymous
    • one year ago
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    so just A is right?

  7. DanJS
    • one year ago
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    what is sin(theta 0if cos(theta) = 3/5 ?

  8. DanJS
    • one year ago
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    sin^2(theta) + cos^2 (theta) = 1

  9. anonymous
    • one year ago
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    sin theta= 4/5

  10. anonymous
    • one year ago
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    Are A and B the corect answers?

  11. DanJS
    • one year ago
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    remember it is the 4th quadrant, the sin will be negative

  12. anonymous
    • one year ago
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    can you just tell me if im right

  13. DanJS
    • one year ago
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    you know sin and cos, check the other 2 answers B and C csc = 1 / sin = 5/4 ?

  14. DanJS
    • one year ago
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    tan = sin / cos = 4 / 3 ?

  15. anonymous
    • one year ago
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    it cant be C because tangent has to be negative

  16. DanJS
    • one year ago
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    yes!

  17. anonymous
    • one year ago
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    I already knew that. I am asking if A and B are the correct answers

  18. DanJS
    • one year ago
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    yes, we showed cos(theta) = 3 /5 so A is right. You calculated sin(theta) = -4/5

  19. DanJS
    • one year ago
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    so csc(theta) = 1 / sin(theta) = -5/4

  20. anonymous
    • one year ago
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    so are u saying B is right ?

  21. DanJS
    • one year ago
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    no, csc(theta) is negative

  22. DanJS
    • one year ago
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    sin is -4/5 so 1 / sin is also negative

  23. anonymous
    • one year ago
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    so csc has to be -5/4 to be true

  24. DanJS
    • one year ago
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    yeah

  25. anonymous
    • one year ago
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    thank you.

  26. DanJS
    • one year ago
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    so A is the only one it looks like

  27. DanJS
    • one year ago
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    welcome

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