anonymous
  • anonymous
if sec(θ)= 5/3 and the terminal point determined by θ is in quadrant 4, then CHECK ALL THAT APPLIES A. cos (θ)=3/5 B. csc (θ)= 5/4 C. tan (θ)= 4/3 D. sin (θ) = -(2/5)
Mathematics
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anonymous
  • anonymous
if sec(θ)= 5/3 and the terminal point determined by θ is in quadrant 4, then CHECK ALL THAT APPLIES A. cos (θ)=3/5 B. csc (θ)= 5/4 C. tan (θ)= 4/3 D. sin (θ) = -(2/5)
Mathematics
schrodinger
  • schrodinger
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DanJS
  • DanJS
sec(theta) = 1 / cos(theta)
anonymous
  • anonymous
what does that mean
DanJS
  • DanJS
sec(theta) = 1 / cos(theta) = 5 / 3 solve for cos(theta)

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DanJS
  • DanJS
in quadrant 4, cos(theta) is positive
DanJS
  • DanJS
( x, y ) = ( cos(theta) , sin(theta) ) 4th quadrant, positive X value, positive cos value
anonymous
  • anonymous
so just A is right?
DanJS
  • DanJS
what is sin(theta 0if cos(theta) = 3/5 ?
DanJS
  • DanJS
sin^2(theta) + cos^2 (theta) = 1
anonymous
  • anonymous
sin theta= 4/5
anonymous
  • anonymous
Are A and B the corect answers?
DanJS
  • DanJS
remember it is the 4th quadrant, the sin will be negative
anonymous
  • anonymous
can you just tell me if im right
DanJS
  • DanJS
you know sin and cos, check the other 2 answers B and C csc = 1 / sin = 5/4 ?
DanJS
  • DanJS
tan = sin / cos = 4 / 3 ?
anonymous
  • anonymous
it cant be C because tangent has to be negative
DanJS
  • DanJS
yes!
anonymous
  • anonymous
I already knew that. I am asking if A and B are the correct answers
DanJS
  • DanJS
yes, we showed cos(theta) = 3 /5 so A is right. You calculated sin(theta) = -4/5
DanJS
  • DanJS
so csc(theta) = 1 / sin(theta) = -5/4
anonymous
  • anonymous
so are u saying B is right ?
DanJS
  • DanJS
no, csc(theta) is negative
DanJS
  • DanJS
sin is -4/5 so 1 / sin is also negative
anonymous
  • anonymous
so csc has to be -5/4 to be true
DanJS
  • DanJS
yeah
anonymous
  • anonymous
thank you.
DanJS
  • DanJS
so A is the only one it looks like
DanJS
  • DanJS
welcome

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