yamyam70
  • yamyam70
Someone Check my work! Determine the Domain See drawing below
Mathematics
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
yamyam70
  • yamyam70
|dw:1437320720884:dw|
yamyam70
  • yamyam70
or would that be [0 , 4] only if we consider the radical inside?
Michele_Laino
  • Michele_Laino
hint: the inner radical exists if \[\Large x \geqslant 0\] furthermore we have the subsequent condition: \[\Large 2 - \sqrt x \geqslant 0\]

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Michele_Laino
  • Michele_Laino
that additional condition, is equivalent to this one: \[\Large 2 \geqslant \sqrt x \]
yamyam70
  • yamyam70
If we consider both conditions , the inner radical and the whole radical, I need to make the inner radical exist, as well as meeting the subsequent condition, thats the rule right ?
Michele_Laino
  • Michele_Laino
yes!
yamyam70
  • yamyam70
lol give me a moment Im trying to think about it
yamyam70
  • yamyam70
oh and I just found out that I cant make x negative
Michele_Laino
  • Michele_Laino
both of those conditions have to be checked
yamyam70
  • yamyam70
im thinking it should be all real numbers except , x would not equal to 0 and 4
Michele_Laino
  • Michele_Laino
hint: starting from this inequality: \[\Large 2 \geqslant \sqrt x \] square both sides, what do you get?
yamyam70
  • yamyam70
\[4 \ge x\]
yamyam70
  • yamyam70
its [ 0 , 4 ] is it ?
Michele_Laino
  • Michele_Laino
correct! furthermore, as I wrote before, we have: \[\Large x \geqslant 0\] so, what can you conclude?
Michele_Laino
  • Michele_Laino
that's right!
yamyam70
  • yamyam70
in overview Im getting the intersection of both conditions right ?
Michele_Laino
  • Michele_Laino
yes!
yamyam70
  • yamyam70
I LOVE YOU
Michele_Laino
  • Michele_Laino
thanks! :)
yamyam70
  • yamyam70
now I feel confident in determining the D :)))))))
Michele_Laino
  • Michele_Laino
:)

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