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yamyam70

  • one year ago

Someone Check my work! Determine the Domain See drawing below

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  1. yamyam70
    • one year ago
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    |dw:1437320720884:dw|

  2. yamyam70
    • one year ago
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    or would that be [0 , 4] only if we consider the radical inside?

  3. Michele_Laino
    • one year ago
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    hint: the inner radical exists if \[\Large x \geqslant 0\] furthermore we have the subsequent condition: \[\Large 2 - \sqrt x \geqslant 0\]

  4. Michele_Laino
    • one year ago
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    that additional condition, is equivalent to this one: \[\Large 2 \geqslant \sqrt x \]

  5. yamyam70
    • one year ago
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    If we consider both conditions , the inner radical and the whole radical, I need to make the inner radical exist, as well as meeting the subsequent condition, thats the rule right ?

  6. Michele_Laino
    • one year ago
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    yes!

  7. yamyam70
    • one year ago
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    lol give me a moment Im trying to think about it

  8. yamyam70
    • one year ago
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    oh and I just found out that I cant make x negative

  9. Michele_Laino
    • one year ago
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    both of those conditions have to be checked

  10. yamyam70
    • one year ago
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    im thinking it should be all real numbers except , x would not equal to 0 and 4

  11. Michele_Laino
    • one year ago
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    hint: starting from this inequality: \[\Large 2 \geqslant \sqrt x \] square both sides, what do you get?

  12. yamyam70
    • one year ago
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    \[4 \ge x\]

  13. yamyam70
    • one year ago
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    its [ 0 , 4 ] is it ?

  14. Michele_Laino
    • one year ago
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    correct! furthermore, as I wrote before, we have: \[\Large x \geqslant 0\] so, what can you conclude?

  15. Michele_Laino
    • one year ago
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    that's right!

  16. yamyam70
    • one year ago
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    in overview Im getting the intersection of both conditions right ?

  17. Michele_Laino
    • one year ago
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    yes!

  18. yamyam70
    • one year ago
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    I LOVE YOU

  19. Michele_Laino
    • one year ago
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    thanks! :)

  20. yamyam70
    • one year ago
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    now I feel confident in determining the D :)))))))

  21. Michele_Laino
    • one year ago
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    :)

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