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anonymous

  • one year ago

ΔABC is translated 2 units down and 1 unit left. Then it is rotated 90° clockwise about the origin to create ΔA′B′C′. What are the coordinates of the vertices of ΔA′B′C′ ? a) A′(-2, 0), B′(1, -1), C′(-1, -1) b) A′(2, 1), B′(5, 0), C′(3, 0) c) A′(-1, -2), B′(2, -3), C′(0, -3) d) A′(-2, 1), B′(1, 0), C′(-1, 0) http://cdn.ple.platoweb.com/PCAP-ASSETS-PROD/3978bcffcb214850a36be077c84be2b9

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  1. Mehek14
    • one year ago
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    Lets start by A

  2. Mehek14
    • one year ago
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    A(0-1,0-2) 0-1 = -1 0 - 2 = -2 so when A is translated, its ordered pair becomes (-1,-2)

  3. anonymous
    • one year ago
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    ok thanks i really don't know to much about geometry so

  4. Mehek14
    • one year ago
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    now we need to rotate that 90 clockwise the rule for that is (y,-x)

  5. anonymous
    • one year ago
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    ok

  6. Mehek14
    • one year ago
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    so if we put the ordered pair for A into (y,-x) we get -2, 1

  7. Mehek14
    • one year ago
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    that is the ordered pair for A'

  8. anonymous
    • one year ago
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    so the answer is a ?

  9. Mehek14
    • one year ago
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    If you want, we can find the ordered pairs for B and C but only 1 answer choice has (-2,1) for A

  10. Mehek14
    • one year ago
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    no not A look for A'(-2,1)

  11. anonymous
    • one year ago
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    ok yes we can do it

  12. Mehek14
    • one year ago
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    ok lets move on to B

  13. anonymous
    • one year ago
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    ok

  14. Mehek14
    • one year ago
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    ordered pair (1,3) 2 units down 3-2 = 1 1 unit to the left 1-1 = 0 (0,1) rotation 90 clockwise (1,0) so B'(1,0)

  15. Mehek14
    • one year ago
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    C (1,1) 2 units down 1-2=-1 1 unit to the left 1-1=0 (0,-1) rotation (-1,0)

  16. Mehek14
    • one year ago
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    so A′(-2, 1), B′(1, 0), C′(-1, 0)

  17. Mehek14
    • one year ago
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    Did you get it?

  18. anonymous
    • one year ago
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    yes

  19. anonymous
    • one year ago
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    so the answer is ?

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