anonymous
  • anonymous
ΔABC is translated 2 units down and 1 unit left. Then it is rotated 90° clockwise about the origin to create ΔA′B′C′. What are the coordinates of the vertices of ΔA′B′C′ ? a) A′(-2, 0), B′(1, -1), C′(-1, -1) b) A′(2, 1), B′(5, 0), C′(3, 0) c) A′(-1, -2), B′(2, -3), C′(0, -3) d) A′(-2, 1), B′(1, 0), C′(-1, 0) http://cdn.ple.platoweb.com/PCAP-ASSETS-PROD/3978bcffcb214850a36be077c84be2b9
Mathematics
jamiebookeater
  • jamiebookeater
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Mehek14
  • Mehek14
Lets start by A
Mehek14
  • Mehek14
A(0-1,0-2) 0-1 = -1 0 - 2 = -2 so when A is translated, its ordered pair becomes (-1,-2)
anonymous
  • anonymous
ok thanks i really don't know to much about geometry so

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Mehek14
  • Mehek14
now we need to rotate that 90 clockwise the rule for that is (y,-x)
anonymous
  • anonymous
ok
Mehek14
  • Mehek14
so if we put the ordered pair for A into (y,-x) we get -2, 1
Mehek14
  • Mehek14
that is the ordered pair for A'
anonymous
  • anonymous
so the answer is a ?
Mehek14
  • Mehek14
If you want, we can find the ordered pairs for B and C but only 1 answer choice has (-2,1) for A
Mehek14
  • Mehek14
no not A look for A'(-2,1)
anonymous
  • anonymous
ok yes we can do it
Mehek14
  • Mehek14
ok lets move on to B
anonymous
  • anonymous
ok
Mehek14
  • Mehek14
ordered pair (1,3) 2 units down 3-2 = 1 1 unit to the left 1-1 = 0 (0,1) rotation 90 clockwise (1,0) so B'(1,0)
Mehek14
  • Mehek14
C (1,1) 2 units down 1-2=-1 1 unit to the left 1-1=0 (0,-1) rotation (-1,0)
Mehek14
  • Mehek14
so A′(-2, 1), B′(1, 0), C′(-1, 0)
Mehek14
  • Mehek14
Did you get it?
anonymous
  • anonymous
yes
anonymous
  • anonymous
so the answer is ?

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