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clara1223

  • one year ago

Find a solution set to equation (equation and answer choices in comments)

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  1. clara1223
    • one year ago
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    \[4x ^{2}-2=2x ^{2}+x+16\] \[a) \frac{ 9 }{ 4 }-\frac{ 1 }{ 4 }\sqrt{65}, \frac{ 9 }{ 4 }+\frac{ 1 }{ 4 }\sqrt{65}\] \[b) \frac{ 1 }{ 4 }-\frac{ 1 }{ 4 }\sqrt{65}, \frac{ 1 }{ 4 }+\frac{ 1 }{ 4 }\sqrt{65}\] \[c) -\frac{ 1 }{ 4 }+\frac{ 1 }{ 4 }\sqrt{65}, \frac{ 1 }{ 8 }+\frac{ 1 }{ 8 }\sqrt{65}\] \[d) -\frac{ 1 }{ 4 }-\frac{ 1 }{ 4 }\sqrt{65}, -\frac{ 1 }{ 4 }+\frac{ 1 }{ 4 }\sqrt{65}\] \[e) \frac{ 1 }{ 2 }-\frac{ 1 }{ 2 }\sqrt{65}, \frac{ 1 }{ 2 }+\frac{ 1 }{ 2 }\sqrt{65}\]

  2. paki
    • one year ago
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    +4x^2−2=2x^2+x+16 +4x^2-2x^2-x-2-16=0 can you solve it now...? then use quadratic formula or solve it by factorization....

  3. clara1223
    • one year ago
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    oops that 16 is supposed to be a 6. But yes, thanks for the help! @paki

  4. paki
    • one year ago
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    my pleasure...

  5. clara1223
    • one year ago
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    @paki I got \[\frac{ 1\pm \sqrt{65} }{ 4 }\] does that mean the answer is b?

  6. paki
    • one year ago
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    http://prntscr.com/7uj2zo

  7. clara1223
    • one year ago
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    @paki thanks so much!

  8. paki
    • one year ago
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    my pleasure... @clara1223

  9. anonymous
    • one year ago
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    HHAAAAYYYY

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