## anonymous one year ago Find a solution set to equation (equation and answer choices in comments)

1. anonymous

$4x ^{2}-2=2x ^{2}+x+16$ $a) \frac{ 9 }{ 4 }-\frac{ 1 }{ 4 }\sqrt{65}, \frac{ 9 }{ 4 }+\frac{ 1 }{ 4 }\sqrt{65}$ $b) \frac{ 1 }{ 4 }-\frac{ 1 }{ 4 }\sqrt{65}, \frac{ 1 }{ 4 }+\frac{ 1 }{ 4 }\sqrt{65}$ $c) -\frac{ 1 }{ 4 }+\frac{ 1 }{ 4 }\sqrt{65}, \frac{ 1 }{ 8 }+\frac{ 1 }{ 8 }\sqrt{65}$ $d) -\frac{ 1 }{ 4 }-\frac{ 1 }{ 4 }\sqrt{65}, -\frac{ 1 }{ 4 }+\frac{ 1 }{ 4 }\sqrt{65}$ $e) \frac{ 1 }{ 2 }-\frac{ 1 }{ 2 }\sqrt{65}, \frac{ 1 }{ 2 }+\frac{ 1 }{ 2 }\sqrt{65}$

2. paki

+4x^2−2=2x^2+x+16 +4x^2-2x^2-x-2-16=0 can you solve it now...? then use quadratic formula or solve it by factorization....

3. anonymous

oops that 16 is supposed to be a 6. But yes, thanks for the help! @paki

4. paki

my pleasure...

5. anonymous

@paki I got $\frac{ 1\pm \sqrt{65} }{ 4 }$ does that mean the answer is b?

6. paki
7. anonymous

@paki thanks so much!

8. paki

my pleasure... @clara1223

9. anonymous

HHAAAAYYYY