anonymous
  • anonymous
Help needed again? Rationalize the denominator and simplify.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\frac{ 2\sqrt{x}-3\sqrt{y} }{ \sqrt{x}+\sqrt{y} }\]
Owlcoffee
  • Owlcoffee
You might want to use the conjugate formula: \[\sqrt a - \sqrt b = \frac{ a-b }{ \sqrt a + \sqrt b }\]
anonymous
  • anonymous
Well I know the conjugate formula. Its doing the actual math that always seems to ruin the result.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I know to multiply it by \[\frac{ \sqrt{x}-\sqrt{y} }{ \sqrt{x}-\sqrt{y} }\]
anonymous
  • anonymous
What I am specifically having trouble with is multiplying the numerator.
Owlcoffee
  • Owlcoffee
Try forming a square difference.
Owlcoffee
  • Owlcoffee
\[\frac{ 2\sqrt x - 3 \sqrt y }{\sqrt x +\sqrt y }\frac{ ( \sqrt x - \sqrt y) }{ (\sqrt x - \sqrt y) }\] \[\frac{ 2x-2\sqrt x \sqrt y -3 \sqrt y \sqrt x +3y }{ x-y }\] \[\frac{ 2x-5 \sqrt x \sqrt y +3y }{ x-y }\] This is what you get if you multiply to what you suggested.

Looking for something else?

Not the answer you are looking for? Search for more explanations.