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anonymous
 one year ago
Please help with Algebra will award medal
anonymous
 one year ago
Please help with Algebra will award medal

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Task 2 Part 1. Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model. a√x+b+c=d Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation. Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneous. Part 3. Explain why the first equation has an extraneous solution and the second does not.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0An extraneous solution is a fake result. You can go through and solve the equation, but when you check the answer it won't work. The easiest thing to do for both equations is to make a = 1 so you don't have to worry about division. Then you're left with \(\sqrt{x+b}+c=d\) Subtract c from both sides to get \(\sqrt{x+b}=dc\) For the extraneous solution equation, you need dc to be negative. For the other one dc will be positive.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I can choose any number or does It have to be specific

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can choose any number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I plug in the numbers ad solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I couldn't see anything in that file. Can you post a screenshot or use the draw tool?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok I plugged In numbers a radical sign 18 +24+32=46

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I subtract the 32 from both sides now right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you're still supposed to have a radical sign and an x. The only numbers you're replacing are a,b,c, and d. For example √(x3)+4=20

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For that equation a =1, b=3, c = 4, and d = 20. Check d  c: d  c = 20  4 = 16 This is positive so that's an equation without an extraneous solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I don't need to add a number for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So so I subtract 4 from both sides and then now I have 1\ x+3=16 sorry I don't have a radical sign on my keyboard lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I keep simplifying the equation from there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes after you subtract 4 square both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok now I have 1/ x + 3 =16

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Than I subtracted 3 from both sides and now it's just 1/x=13

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, square both sides first then subtract 3. You can't subtract the 3 while it's under the radical.dw:1437332991847:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Square the 3 also or no

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, the whole thing under the radical is squared. The √ and ² cancel each other \[\sqrt{x3}^2=x3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok so x + 3 =256 so do I subtract the three now or leave it as it is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0253? Just realized we switched for x3 to x+3 when we were solving it. Just change the sign in the original equation to +

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the extraneous equation, just swap c and d and go through the same steps √(x3)+20=4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok I just finished that part now how would I explain why the first one was extraneous do I just say because the answer doesn't go with the equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, the answer doesn't check
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