anonymous
  • anonymous
please help!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
DanJS
  • DanJS
put it in standard form first ax^2 + bx + c = 0 c is negative 5, not plus 5
anonymous
  • anonymous
okay

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anonymous
  • anonymous
so the mistake starts from the first step?
Michele_Laino
  • Michele_Laino
hint: your equation is: \[{x^2} + 4x - 5 = 0\]
anonymous
  • anonymous
i got that part:)
anonymous
  • anonymous
a=1,b=4,c=-5
Michele_Laino
  • Michele_Laino
yes! the right answer is: \[\begin{gathered} x = \frac{{ - 4 \pm \sqrt {{{\left( { - 4} \right)}^2} - 4 \times 1 \times \left( { - 5} \right)} }}{{2 \times 1}} = \hfill \\ \hfill \\ = \frac{{ - 4 \pm \sqrt {16 + 20} }}{2} = \frac{{ - 4 \pm 6}}{2} = ...? \hfill \\ \end{gathered} \]
anonymous
  • anonymous
1 and -5
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
but i need to explain where the student went wrong
anonymous
  • anonymous
does she go wrong since the beginning because she put 5 instead of -5?
Michele_Laino
  • Michele_Laino
the student was wrong, since the coefficient c is -5 not +5
Michele_Laino
  • Michele_Laino
namely: \[\Large c = - 5\] before applying the formula: \[\Large x = \frac{{ - b \pm \sqrt {{b^2} - 4 \times a \times c} }}{{2 \times a}}\] we have to write our quadratic equation, in this form: \[\Large a{x^2} + bx + c = 0\]
anonymous
  • anonymous
okay, thanks so much!! :)
Michele_Laino
  • Michele_Laino
thanks!

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