Solve: sin^(2) x - Sin x =0, for 0≤x≤3

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Solve: sin^(2) x - Sin x =0, for 0≤x≤3

Mathematics
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here we have to change variable, namely: \[\Large \sin x = t\]
after that your equation can be rewritten as follows: \[\Large {t^2} - t = 0\]
please solve that equation for t

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Other answers:

So t=0?
hint, we can factor out t at left side, so we can write: \[\Large t\left( {t - 1} \right) = 0\]
Oh, so t= 0 and 1?
that's right!
now t=0 means: sin x=0 what is x?
x= Radical 3 over 2?
Oops!
no, the solution of that equation: sin x=0, are: \[x = 0,\pi ,2\pi ,3\pi ...\]
nevertheless only x=0, is acceptable, since pi >3
Oh, i get it! Thank you!
please wait, we have to solve this equation: t=1 which means sin x =1
for which values x, we have: sin x= 1?
\[\sin x = 1 \Rightarrow x = ...?\]
Pie over 2 and 3 pie over 2
no, the solutions are: \[x = \frac{\pi }{2},2\pi + \frac{\pi }{2},4\pi + \frac{\pi }{2}...\]
Oh yea, my bad.
nevertheless only x= pi/2 is acceptable
I get it. thanks :D
thanks! :)

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